Here is the table with the filled in answers
Answer: sure
Step-by-step explanation:
The greatest common factor is to h4 and h8 is 4
Correct Answer:
C option: 6 feetSolution:Since <span>Yolanda wants to keep the pool in proportion to the model, the ratio of diameter to depth of model and the pool will be same.
Let the depth of pool is x feet. So we can write:
Ratio of Diameter to Depth of Model = Ratio of Diameter to Depth of pool
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This means the depth of pool should be 6 feet if </span><span>Yolanda wants to keep the pool in proportion to the model.</span>
Complete question is:
Seventy million pounds of trout are grown in the U.S. every year. Farm-raised trout contain an average of 32 grams of fat per pound, with a standard deviation of 7 grams of fat per pound. A random sample of 34 farm-raised trout is selected. The mean fat content for the sample is 29.7 grams per pound. Find the probability of observing a sample mean of 29.7 grams of fat per pound or less in a random sample of 34 farm-raised trout. Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.
Answer:
Probability = 0.0277
Step-by-step explanation:
We are given;
Mean: μ = 32
Standard deviation;σ = 7
Random sample number; n = 34
To solve this question, we would use the equation z = (x - μ)/(σ/√n) to find the z value that corresponds to 29.7 grams of fat.
Thus;
z = (29.7 - 32)/(7/√34)
Thus, z = -2.3/1.200490096
z = -1.9159
From the standard z table and confirming with z-calculator, the probability is 0.0277
Thus, the probability to select 34 fish whose average grams of fat per pound is less than 29.7 = 0.0277