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elixir [45]
2 years ago
9

A number cube is rolled 450 times and the

Mathematics
1 answer:
EleoNora [17]2 years ago
7 0

Answer:

A.) 0.33

Step-by-step explanation:

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Ira Lisetskai [31]
I think the answer is letter B
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3 years ago
Given the following roots build a polynomial function in standard form: -3 and +2
swat32

Answer:

  f(x) = x² +x -6

Step-by-step explanation:

The standard form will look like ...

  f(x) = x² +bx +c

where b is the opposite of the sum of the roots, and c is their product.

  f(x) = x² -(-3+2)x +(-3)(2)

  f(x) = x² +x -6

_____

<em>Additional comment</em>

In general, "standard form" is ax²+bx+c. In this case, the coefficient 'a' can be 1 since neither of the roots is expressed as a fraction. The sum of roots is (-b/a) and the product of roots is (c/a).

3 0
3 years ago
Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)
Mashcka [7]
The cone equation gives

z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2

which means that the intersection of the cone and sphere occurs at

x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92

i.e. along the vertical cylinder of radius \dfrac3{\sqrt2} when z=\dfrac3{\sqrt2}.

We can parameterize the spherical cap in spherical coordinates by

\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle

where 0\le\theta\le2\pi and 0\le\varphi\le\dfrac\pi4, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is \dfrac3{\sqrt2}. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

Now the surface area of the cap is given by the surface integral,

\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du
=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du
=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}
=18\pi\left(1-\dfrac1{\sqrt2}\right)
=9(2-\sqrt2)\pi
3 0
3 years ago
Fill in the missing fraction or mixed number <br> __ + 1/4 = 5/8
gogolik [260]

3/8=answer

1) 5/8-1/4=

2) <u>(</u><u>5</u><u>•</u><u>4</u><u>)</u><u>-</u><u>(</u><u>1</u><u>•</u><u>8</u><u>)</u><u>=</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>8•4

3) <u>20-8</u><u> </u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>32 =

4) <u>12</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>32=

5) <u>12</u><u>/</u><u>4</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>32/4=

6) <u>3</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>8 =answer

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3 years ago
Solve x 2 + 8x + 7 = 0<br> {-1,-7)<br> {1,7)<br> 00
IgorLugansk [536]
X^2 + 8x + 7= 0
(X+7)(X+1)
X=-1,-7
3 0
3 years ago
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