Answer:
a) Sample size = 822
b) Margin of error = 0.03407
Step-by-step explanation:
We are given the following in the question:
p = 74% = 0.74
a) Sample size is required to obtain margin of error of 0.03
Formula:


Putting values, we get,

Thus, the sample size must be approximately 822 to obtain a 95% confidence interval with an approximate margin of error of 0.03
b) Margin of error for the 95% confidence interval
p = 54% = 0.54
Formula:


Putting values, we get,

The margin of error now will be 0.03407.
Answer:
400milliliters
Step-by-step explanation:
Let x=ml of 30% solution B used in resulting mixture.
800+x=ml of resulting 30% solution
40%(800)+10%x=30%(800+x)
Then we can simplify the expression
0.4(800)+0.10x= 0.30(800+x)
320+0.10x=240+0.30x
80=0.20x
x= 400milliliters
Therefore, 400milliliters of 10% solution B used in resulting mixture.
Answer:
4189
Step-by-step explanation:
Given sequence is:

Plugging n = 57 in the given sequence, we find:



Answer:
a b
Step-by-step explanation: