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Blababa [14]
3 years ago
7

Suppose you carry out a significance test of h0: μ = 8 versus ha: μ > 8 based on sample size n = 25 and obtain t = 2. 15. Fin

d the p-value for this test. What conclusion can you draw at the 5% significance level? explain.
a the p-value is 0. 2. We reject h0 at the 5% significance level because the p-value 0. 02 is less than 0. 5.
b the p-value is 0. 2. We fail to reject h0 at the 5% significance level because the p-value 0. 02 is less than 0. 5.
c the p-value is 0. 48. We reject h0 at the 5% significance level because the p-value 0. 48 is greater than 0. 5.
d the p-value is 0. 48. We fail to reject h0 at the 5% significance level because the p-value 0. 48 is greater than 0. 5.
e the p-value is 0. 52. We fail to reject h0 at the 5% significance level because the p-value 0. 52 is greater than 0. 5
Mathematics
1 answer:
OLEGan [10]3 years ago
5 0

Using a t-distribution calculator and finding the p-value, the correct option regarding the conclusion is given by:

a) the p-value is 0.02. We reject h0 at the 5% significance level because the p-value 0.02 is less than 0.05.

<h3>What is the relation between the p-value and the conclusion?</h3>

It also involves the significance level, as follows.

  • If the p-value is less than the significance level, we reject the null hypothesis h_0.
  • If it is more, we do not reject.

In this problem, a t-distribution calculator for a right-tailed  with <em>t = 2.15 and 25 - 1 = 24 df</em> is used to find a p-value of 0.02.

It is less than 0.05, hence option a is correct.

More can be learned about p-values at brainly.com/question/26454209

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7nadin3 [17]

Answer:

See below.

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(b) A solution was found by introducing the operator i which stands for the square root of -1.

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(c) Substituting in the original equation:

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=  25 - 15 - 50 + 40

= 0.   So this checks out.

Now substitute 5 - √(-15)i

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=  25 - 15 - 50 + 40

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