All categories

1 year ago

Find the area of the shaded region

Mathematics

2 answers:

DochEvi [55]1 year ago

7 0

Answer:

20.52 cm²

<h3><u>Area of shaded region:</u></h3>

area of semi-circle - area of triangle

$\dashrightarrow \sf \dfrac{1}{2} \ \pi (radius)^2 \ - \ \sf \dfrac{1}{2} *base*height$

$\rightarrow \sf \dfrac{1}{2} (3.14)(6)^2 - \dfrac{1}{2} *12*6$

$\hookrightarrow \sf 56.52 \ - \ 36$

$\hookrightarrow \sf 20.52 \ cm^2$

grandymaker [24]1 year ago

5 0

Not getting in to too much details but basically
Area of half circle - area of triangle
3.14r^2-1/2bh
r=6 b=12 h=6

You might be interested in

Let f be a differentiable function such that f(3)=15, f(6)=3, f ' (3)= -8, and f ' (6)= -2. The function g is differentiable and

Ray Of Light [21]

Answer:

A. $g'(3)=-\frac{1}{2}$

Step-by-step explanation:

We have been given that f be a differentiable function such that $f(3)=15$ , $f(6)=3$ , $f'(3)= -8$ , and $f'(6)= -2$ . The function g is differentiable and $g(x)= f^{-1} (x)$ for all x.

We know that when one function is inverse of other function, so:

$g(f(x))=x$

Upon taking derivative of both sides of our equation, we will get:

$g'(f(x))*f'(x) =1$

$g'(f(x))=\frac{1}{f'(x)}$

Plugging $x=6$ into our equation, we will get:

$g'(f(6))=\frac{1}{f'(6)}$

Since $g(x)= f^{-1} (x)$ , then $g'(f(6))=g'(3)$ .

$g'(3)=\frac{1}{f'(6)}$

Since we have been given that $f'(6)= -2$ , so we will get:

$g'(3)=\frac{1}{-2}$

$g'(3)=-\frac{1}{2}$

Therefore, $g'(3)=-\frac{1}{2}$ and option A is the correct choice.

8 0

3 years ago

Which ordered pair is a solution to the system of linear equations 1/2x-3/4y=11/60 and 2/5x+1/6y=3/10

natka813 [3]

ANSWER

$( \frac{2}{3} , \frac{1}{5} )$

EXPLANATION

The first equation is

$\frac{1}{2} x - \frac{3}{4} y = \frac{11}{60} ...(1)$

The second equation is

$\frac{2}{5} x + \frac{1}{6} y = \frac{3}{10} ...(2)$

We want to eliminate y, so we multiply the first equation by

$\frac{4}{5}$

$\frac{4}{5} \times \frac{1}{2} x - \frac{4}{5} \times \frac{3}{4} y = \frac{11}{60} \times \frac{4}{5}$

$\frac{2}{5} x - \frac{3}{5} y = \frac{11}{75} ...(3)$

We now subtract equation (3) from (2)

$(\frac{2}{3} x - \frac{2}{3} x )+ ( \frac{1}{6} y - - \frac{3}{5}y ) =( \frac{3}{10} - \frac{11}{75} )$

$\frac{1}{6} y + \frac{3}{5}y =\frac{3}{10} - \frac{11}{75}$

$\frac{23}{30}y = \frac{23}{150}$

Multiply both sides by

$\frac{30}{23}$

$\implies \: \frac{30}{23} \times \frac{23}{30}y= \frac{23}{150} \times \frac{30}{23}$

$\implies \: y = \frac{1}{5}$

Substitute into the first equation to solve for x .

$\frac{1}{2} x - \frac{3}{4} \times \frac{1}{5} = \frac{11}{60}$

Multiply to obtain

$\frac{1}{2} x - \frac{3}{20} = \frac{11}{60}$

$\frac{1}{2} x = \frac{11}{60} + \frac{3}{20}$

$\frac{1}{2} x = \frac{1}{3}$

Multiply both sides by 2.

$2 \times \frac{1}{2} x =2 \times \frac{1}{3}$

$x = \frac{2}{3}$

The solution is

$( \frac{2}{3} , \frac{1}{5} )$

5 0

2 years ago

Read 2 more answers

john can eat 13 cupcakes in 4 minutes. how many cupcakes can john eat per minute? make sure your answer has labels

sergejj [24]

Answer:

3.25 cupcakes per minute or a rate of 3.25/1

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

A} work out exact value of 13822 x 623/14

grigory [225]

Answer:

615079

Step-by-step explanation:

This is the answer for A

6 0

3 years ago

Please help!! Math homework

Hitman42 [59]

<h3><u>Answer:</u></h3>

x = 66°
y = 48°

<h3><u>Step-by-step explanation:</u></h3>

<u>Since this is an isosceles triangle, the base angles must be the same. Hence, </u><u>x = 66°.</u>

<u>Since we have found x, we can find y by using the 180-angle method.</u>

=> y + 66 + 66 = 180
=> y + 132 = 180
=> y = 180 - 132
=> y = 48°

<h3><u>Conclusion:</u></h3>

Therefore, the answers are:

x = 66°
y = 48°

Hoped this helped.

$BrainiacUser1357$

4 0

2 years ago