we know that
m∠SQR+x=
-------> by supplementary angles
so
m∠SQR=
The sum of the internal angles of a triangle is equal to
degrees
m∠SQR+m∠QSR+m∠SRQ=
substitute the values in the formula
m∠SQR+
+
=
m∠SQR=
degrees
<u>Find the value of x</u>
m∠SQR=
x=
-m∠SQR
x=
x=
degrees
therefore
<u>the answer is</u>
the value of x is
degrees
Answer:
It's 4.75
Step-by-step explanation:
If you subtract 5-.25=? The answer would be 4.75. Hope this helps.
Answer:
+120/169 or -120/169
Step-by-step explanation:
- let
![cos^{-1}[\frac{5}{13} ] = \alpha](https://tex.z-dn.net/?f=cos%5E%7B-1%7D%5B%5Cfrac%7B5%7D%7B13%7D%20%20%5D%20%3D%20%5Calpha)
where, alpha is some angle that satisfies the assumed condition.
- so,

[ taking cos to the other side or applying cos on both sides]
- now, substitute this in the given expression
as sin
= 
[by general trigonometry formula:
]
so if
, we can get sin
from the above formula as + or - 12/13
(because, after taking square root on both sides we keep + or -]
- as, sin
![2\beta = 2*sin[\beta ]*cos[\beta ]](https://tex.z-dn.net/?f=2%5Cbeta%20%20%3D%202%2Asin%5B%5Cbeta%20%5D%2Acos%5B%5Cbeta%20%5D)
[by general trigonometry formula]
- here, now
![sin[2\alpha ]=2*(+or- 12/13)*5/13\\](https://tex.z-dn.net/?f=sin%5B2%5Calpha%20%5D%3D2%2A%28%2Bor-%2012%2F13%29%2A5%2F13%5C%5C)
so, the final value can be 120/169 or -120/169.
Answer:
9.8
Step-by-step explanation:
7.5+2.3y-y
Subtract y
7.5+2.3
Then Add
9.8