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Morgarella [4.7K]
3 years ago
13

Which answer describes the calculations that could be used to solve this problem?

Mathematics
2 answers:
Ber [7]3 years ago
7 0
What you do is add 8+8+8+8+8+8+8 so the simple form is 8x7, and then you subtract 100 and you should get your answer.




faltersainse [42]3 years ago
4 0
D. Since we know that 1 ticket = $8 we would multiply to figure out how much 7 tickets were. (7x$8). And to figure out his change you would subtract the ticket amount from $100 :) Hope this helps
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A parabolic listening device is shaped such that the depth of the bowl depends on its radius and can be represented by the curve
Rus_ich [418]

Answer:

7.428 inches

Step-by-step explanation:

4 0
3 years ago
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5x^{2} + 3x = x^{2} + 7x
Ipatiy [6.2K]
5x^{2} + 3x = x^{2} + 7x\\
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8 0
3 years ago
Simplify,<br> Rewrite the expression in the form 2n.<br> 2.2.2.2.2.2.2.2<br> 2.2.2.2
Nastasia [14]

Answer: 8/4

Step-by-step explanation: if I’m wrong just watch the video for a hint it helps

6 0
2 years ago
Please help with this I am completely stuck on it
vaieri [72.5K]

Answer:

f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4

Step-by-step explanation:

Given:

The function, H(x)=\sqrt[3]{6x^{2}-4}

Solution 1:

Let f(x)=\sqrt[3]{x}

If f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}, then,

\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4

Solution 2:

Let f(x)=\sqrt[3]{x-4}. Then,

f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}

Similarly, there can be many solutions.

7 0
3 years ago
6 1/4 minus 3 5/8 please answer this please
barxatty [35]
6-3=3 
2/8-5/8=3/8
you would have to change the denominator 
5 0
3 years ago
Read 2 more answers
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