Answer:
If one or two bases are deleted the translational frame is altered resulting in a garbled message and nonfunctional product. A deletion of three or more bases leave the reading frame intact. A deletion of one or more codons results in a protein missing one or more amino acids. This may be deleterious or not.
Explanation:
Radiation is the emission or transmission of energy in the form of waves or particles through space or through a material medium.
Lets calculate the parameters of the problem. Suppose that the width is x feet. THen, the length is x+30 feet. The area of this parallelogram is given by the product of length and width, hence x(x+30). This has to be equal to 600.
Hence, x is the solution to the equation x(x+30)=600.
x*x+30x=600 hence x*x+30x-600=0. This is a second degree equation and we can calculate Δ=b*b-4ac=3300. The general solution is given by:
.
Substituting, we get that x=-30/4+
or x=-7.5+25*
. This is the width; the length is given by x+30.
A client consumed approximately 40 g of protein in the past 24 hours. his 24-hour urine collection indicated a urine urea nitrogen of 12 g. his nitrogen balance would be calculated as option(e)i.e, -9.6 g.
A clear urine signal indicates adequate hydration and maybe overhydration. A healthy level of hydration is indicated by pale yellow urine. More fluids should be consumed if your urine is dark yellow. Urine with an amber hue may be a sign of dehydration. Orange urine is a common side effect of many meals and drugs as well as a potential indicator of liver issues.
It is possible to fertilize with urine. It serves as a territorial marking for some animals. In the past, aged or fermented urine (also known as lant) was used to make gunpowder, clean homes, tan leather, and color fabrics.
Equation: N2 balance = (dietary protein intake/6.25) - (urine urea nitrogen +4)
N2 balance = ( 40/ 6.25) - ( 12 + 4)
N2 balance = - 9.6g
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The complete question is:
A client consumed approximately 40 g of protein in the past 24 hours. His 24-hour urine collection indicated a urine urea nitrogen of 12 g. His nitrogen balance would be:
Equation: N2 balance = (dietary protein intake/6.25) - (urine urea nitrogen +4)
a.) -12.1 g
b.) -4.2 g
c.) 9.6 g
d.) 4.2 g
e.) -9.6 g
