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2 years ago

6

When designing a training plan, what do you need to think about?

1 answer:

Charra [1.4K]2 years ago

7 0

D. Frequency, overtraining, time

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Rewrite the fraction as a decimal.

Roman55 [17]

.3334 is the closest to the actual answer because 1/3 is a repeating decimal

7 0

3 years ago

Read 2 more answers

How am I supposed to find ‘t’ here?

Softa [21]

You can solve for (T)

$y = - 16t {}^{2} + 400 \\ add \: both \: side \: by \: - 16t {}^{2} \\ - 16t {}^{2} = - 400 \\ divide \: both \: side \: by16 \\ t {}^{2} = - 25 \\ t = \sqrt{25} \\ t = 5 \\ \: also \: it \: can \: be \: - 5 \\ + - 5 \\ \\$

Hope this help :)

6 0

3 years ago

Hey please help i’ll give brain

Readme [11.4K]

Answer:

The answer is 2. It is the commutative property of addition. This states that the order of numbers does not matter in addition or multiplication. As long as all the numbers are there, it will give the same answer :)

Step-by-step explanation:

8 0

3 years ago

Solve by completing a square r^2-8r+9

Tanzania [10]

Solving $r^2-8r+9$ by completing a square gives $(r+4)^2-7$

Step-by-step explanation:

We need to solve the equation $r^2-8r+9$ by completing a square

The completing a square method requires: $a^2\pm 2ab +b^2=(a\pm b)^2$

Solving:

$r^2-8r+9\\=(r)^2-2(r)(?)+(?)^2+9$

We need to add and subtract (4)^2=16 to make the equation a complete square

$=(r)^2-2(r)(4)+(4)^2-(4)^2+9\\=(r)^2-2(r)(4)+(4)^2-16+9\\=(r)^2-2(r)(4)+(4)^2-7\\=(r+4)^2-7$

So, Solving $r^2-8r+9$ by completing a square gives $(r+4)^2-7$

Keywords: Solve by completing a square

Learn more about Solve by completing a square at:

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7 0

3 years ago

Which best explains whether 9 is a solution to the inequality x greater-than 9? It is not a solution because 9 is not greater th

patriot [66]

Answer:

"It is not a solution because 9 is not greater than 9."

Step-by-step explanation:

$x>9\\$

If x is 9, then the inequality would be untrue because x must be GREATER than 9 not equal or greater.

5 0

3 years ago