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Vlad1618 [11]
2 years ago
10

Bailey rolls a pair of dice 12 times, and the sum of 6 came up 5 times to calculate the experimental and theoretical probabiliti

es of rolling a sum of six with a pair of dice
Mathematics
1 answer:
mel-nik [20]2 years ago
3 0

Answers:

Experimental probability =  5/12

Theoretical probability = 5/36

========================================================

Explanation:

The experimental probability, aka empirical probability, is what we observe to happen. The event of rolling a six happens 5 times out of 12 total rolls. That leads directly to the experimental probability of 5/12

----------------------------

The theoretical probability is based on predetermined odds, and can be done on paper rather than actually rolling the dice.

There are 6*6 = 36 ways to roll two dice. Of those 36 ways, we have these cases that add to 6

  • 1+5 = 6
  • 2+4 = 6
  • 3+3 = 6
  • 4+2 = 6
  • 5+1 = 6

There are five ways to add to 6, out of 36 outcomes total.

This means the theoretical probability of getting a sum of 6 is 5/36

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Step-by-step explanation:

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Answer:

c

Step-by-step explanation:

<em>To </em><em>find </em><em>the </em><em>midpoint</em><em> </em><em>the </em><em>formulas</em>

<em>x=</em><em>x1+</em><em>x2/</em><em>2</em><em> </em><em>and </em><em>y</em><em>=</em><em>y1+</em><em>y2/</em><em>2</em><em> </em><em>are </em><em>used </em>

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<em>therefore</em>

<em>x=</em><em>5</em><em>+</em><em>5</em><em>/</em><em>2</em><em>. </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

<em> </em><em> </em><em>=</em><em>1</em><em>0</em><em>/</em><em>2</em>

<em> </em><em> </em><em>=</em><em>5</em>

<em>y=</em><em>4</em><em>+</em><em>(</em><em>-</em><em>3</em><em>)</em><em>/</em><em>2</em>

<em> </em><em> </em><em>=</em><em>1</em><em>/</em><em>2</em>

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