Answer:
Class are the collection of variable and member function.
Class are the blueprint of an object.
Explanation:
Following are the points regarding class in c++
1.In C++ class is an user defined datatype..
2.Classes are the collection of variable and function in c++.
3.To access the property of class we can create object of that class
4.We can use following syntax to declared any class in c++
class classname
{
accessmodifier:
//statement and function
};
main()
{
classname objectname;
}
implementation of class in c++
#include<iostream>
class test // class declaration
{
public: // access modifier
void fun3() // Method definition
{
cout<<" hello :";
}
};
void main() // main function
{
test ob;// creating object
ob.fun3(); // calling function
}
In this program we declared a class "test " in class test. We giving public access modifier .The public access modifier define that variable and function are accessible outside the class and in main method we create the object ob which call the function fun3().
Output:hello :
The limpel-ziv (lz77) compression technique is used by the GNU zip (gzip) tool to produce a compression ratio of 60–70%.
<h3>How do methods for data compression function? Describe the LZW algorithm.</h3>
Compression methods lower the amount of memory needed to hold pictures and the number of bytes needed to represent data. Compression improves the amount of data that can be delivered over the internet and enables the storage of more photos on a given media.
Abraham Lempel, Jacob Ziv, and Terry Welch developed the table-based lookup technique known as LZW compression to compress a file into a smaller file. The TIFF image format and the GIF image format are two frequently used file formats that employ LZW compression.
To know more about limpel-ziv (lz77) compression algorithm, Visit:
<u>brainly.com/question/19878993</u>
#SPJ4
Answer:
A = 120
B = 40
C = 70
Solution:
As per the question:
Manufacturer forced to make 10 more type C clamps than the total of A and b:
10 + A + B = C (1)
Also, 3 times as many type B as type A clamps are:
A = 3B (2)
The total no. of clamps produced per day:
A + B + C = 330 (3)
The no. of each type manufactured per day:
Now, from eqn (1), and (3):
A + B + 10 + A + B = 330
2A + 2B = 320
A + B = 160 (4)
Now, from eqn (2) and (4):
3B + B = 160
B = 40
Since, A = 3B
A = 
A = 120
Put the values of A and C in eqn (3):
120 + 40 + C = 330
C = 70
