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bonufazy [111]
2 years ago
10

Bobby spent $12 at the football game Friday night. He spent $2 on nachos, $5 on drinks, $3 on popcorn, and $2 on candy. What per

centage of Bobby's expenses do the nachos and candy represent?
Mathematics
2 answers:
vesna_86 [32]2 years ago
6 0
The answer is 20%

Explanation: he spent 4$ on nachos and candy, over a total of 24. The fraction turns into 1/5 which as a percentage is 20%
Airida [17]2 years ago
3 0

Answer:

33.3%

Step-by-step explanation:

$2 on nachos and $2 on candy will get you $4 spent on them both.

You then have a fraction (4/12)which is 1/3.

1/3=33.3%

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Vsevolod [243]

The only rule to follow is

Divide dividend by divisor and the mention the quotient and things left after remains in place of remainder

Here is a sample

\sf\Large\qquad\quad16\\ \begin{array}{cc} \cline{2 - 2}\sf 20 )&\sf \ 327\\&\sf - 20 \downarrow\\ \cline{2-2}& \sf \ \ \ \ 127\\ &\sf \ - 120 \\ \cline{2-2} & \sf \ \007 \\ \cline{2-2} \end{array}\\\\\\ \sf Divisor \rightarrow 20 \\ \\ \sf Quotient \rightarrow 16\\\\ \sf Remainder \rightarrow 7

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2 years ago
An object has a volume of 7cm³ and a mass of 56g. What is its density in g/cm³?
Nastasia [14]

Answer:8

Step-by-step explanation;Since you want to find the density but you already have the mass you do the inverse operation and divdie 56 by 7 and get 8.

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3 years ago
There are 30 singers in a show. The ratio of singers to dancers is 5:6. How many dancers are there?
Tamiku [17]

Answer: 32 dancers

Step-by-step explanation:

I drew a chart and on the side with the singers you count by 5's until u get to 30. On the dancers side of the chart you count by 6's until it lines up with 30 on the singers side.  

5 0
3 years ago
Read 2 more answers
Your store cost on a dozen eggs is $0.75, and your retail price is $2.99. You are having a promotion that discounts the
posledela

Answer:

$1.94

Step-by-step explanation:

5 0
3 years ago
Match each set of vertices with the type of triangle they form.
Andrew [12]

Answer:  The calculations are done below.


Step-by-step explanation:

(i) Let the vertices be A(2,0), B(3,2) and C(5,1). Then,

AB=\sqrt{(2-3)^2+(0-2)^2}=\sqrt{5},\\\\BC=\sqrt{(3-5)^2+(2-1)^2}=\sqrt{5},\\\\CA=\sqrt{(5-2)^2+(1-0)^2}=\sqrt{10}.

Since, AB = BC and AB² + BC² = CA², so triangle ABC here will be an isosceles right-angled triangle.

(ii) Let the vertices be A(4,2), B(6,2) and C(5,3.73). Then,

AB=\sqrt{(4-6)^2+(2-2)^2}=\sqrt{4}=2,\\\\BC=\sqrt{(6-5)^2+(2-3.73)^2}=\sqrt{14.3729},\\\\CA=\sqrt{(5-4)^2+(3.73-2)^2}=\sqrt{14.3729}.

Since, BC = CA, so the triangle ABC will be an isosceles triangle.

(iii) Let the vertices be A(-5,2), B(-4,4) and C(-2,2). Then,

AB=\sqrt{(-5+4)^2+(2-4)^2}=\sqrt{5},\\\\BC=\sqrt{(-4+2)^2+(4-2)^2}=\sqrt{8},\\\\CA=\sqrt{(-2+5)^2+(2-2)^2}=\sqrt{9}.

Since, AB ≠ BC ≠ CA, so this will be an acute scalene triangle, because all the angles are acute.

(iv) Let the vertices be A(-3,1), B(-3,4) and C(-1,1). Then,

AB=\sqrt{(-3+3)^2+(1-4)^2}=\sqrt{9}=3,\\\\BC=\sqrt{(-3+1)^2+(4-1)^2}=\sqrt{13},\\\\CA=\sqrt{(-1+3)^2+(1-1)^2}=\sqrt 4.

Since AB² + CA² = BC², so this will be a right angled triangle.

(v) Let the vertices be A(-4,2), B(-2,4) and C(-1,4). Then,

AB=\sqrt{(-4+2)^2+(2-4)^2}=\sqrt{8},\\\\BC=\sqrt{(-2+1)^2+(4-4)^2}=\sqrt{1}=1,\\\\CA=\sqrt{(-1+4)^2+(4-2)^2}=\sqrt{13}.

Since AB ≠ BC ≠ CA, and so this will be an obtuse scalene triangle, because one angle that is opposite to CA will be obtuse.

Thus, the match is done.

4 0
4 years ago
Read 2 more answers
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