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anyanavicka [17]
4 years ago
5

I need help with 5 thanks

Mathematics
1 answer:
Mars2501 [29]4 years ago
3 0

For every 3 cups of peanuts there are 2 cups of chocolate

9/3 = 3 so 3*2 = 6

For 9 cups of peanuts there are 6 cups of choclate

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A restaurant chain has two locations in a medium-sized town and, believing that it has oversaturated the market for its food, is
scoray [572]

Answer:

Yes, since the test statistic value is greater than the critical value.

Step-by-step explanation:

Data given and notation

\bar X_{1}=360000 represent the mean for the downtown restaurant

\bar X_{2}=340000 represent the mean for the freeway restaurant

s_{1}=50000 represent the sample standard deviation for downtown

s_{2}=40000 represent the sample standard deviation for the freeway

n_{1}=36 sample size for the downtown restaurant

n_{2}=36 sample size for the freeway restaurant

t would represent the statistic (variable of interest)

\alpha=0.05 significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the true mean of revenue for downtown is higher than for freeway restaurant, the system of hypothesis would be:

Null hypothesis:\mu_{1}\leq \mu_{2}

Alternative hypothesis:\mu_{1} > \mu_{2}

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Determine the critical value.

Based on the significance level\alpha=0.05 and \alpha/2=0.025 we can find the critical values from the t distribution dith degrees of freedom df=36+36-2=55+88-2=70, we are looking for values that accumulates 0.025 of the area on the right tail on the t distribution.

For this case the value is t_{1-\alpha/2}=1.66

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

t=\frac{360000-340000}{\sqrt{\frac{50000^2}{36}+\frac{40000^2}{36}}}}=1.874

What is the p-value for this hypothesis test?

Since is a right tailed test the p value would be:

p_v =P(t_{70}>1.874)=0.033

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the true mean for the downtown revenue restaurant seems higher than the true mean revenue for the freeway restaurant.

The best option would be:

Yes, since the test statistic value is greater than the critical value.

5 0
3 years ago
(13÷6)×8+6. question 2. 10×3+(7+8) please show steps Thank you
AysviL [449]
That is how u would do it

3 0
3 years ago
Read 2 more answers
What is the answer X=-2(6+4)
Digiron [165]

Answer:

X = -20

Step-by-step explanation:

X = -2(6+4)

            ^ add 6 and 4 together first because they are in parentheses

-2(10)

   ^ this parenthesis means you want to multiply -2 and 10

because 2 x 10 = 20

that must mean -2 x 10 = -20

therefore, the value of X is -20

X= -20

3 0
3 years ago
You run 18 miles in 2 hours and 45 miles in 5 hours how fast are you running
Lesechka [4]
So let's find the unit rate of these.

18 mi/ 2 hrs = 9 mi/ 1hr

45 mi / 5 hrs = 9 mi/ 1 hr

So you are running 9 miles an hour.

If you have any questions please comment! :)
6 0
3 years ago
Read 2 more answers
I need help pretty please
ira [324]

Answer:

36

Step-by-step explanation:

3 0
3 years ago
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