Describe the graph of the function. y =Square root of x-1 + 4

Is this an example of a horizontal asymptote?

8_murik_8 [283]

Answer:

Step-by-step explanation:

Hi there,

The graph indicated is showing a horizontal asymptote. In fact, it is showing both a horizontal and a vertical asymptote.

To tell which type it is, notice where the graph "shoots off" and almost forms an imaginary straight line in one direction. Using this logic, the horizontal asymptote will be exactly horizontal, parallel to x-axis, and vertical asymptote will be exactly vertical, parallel to y-axis.

With this graph, we notice the horizontal asymptote is at y=0, where the x-axis is. The vertical asymptote is bit more difficult to determine graphically, but can definitely say it is past x=-10. We could determine it if we had the function, but that is not necessary for this question.

Study well, and persevere. If you liked this solution, leave a Thanks or give a rating!

thanks,

6 0

3 years ago

In the function y=4x^2-5, what effect does the number -5 have on the graph, as compared to the graph of y=x^2

kati45 [8]

It moves the graph 5 steps downwards on the y axis.

3 0

3 years ago

Please help me ineed it now

yanalaym [24]

Answer:

look at explanation

Step-by-step explanation:

To solve all of these questions you just need to scale. While scaling you can divide or multiply.

1. $\frac{180 km}{4 hrs}$ (divide by 4 to get unit rate)

unit rate = $\frac{45km}{1hr}$

2. If it takes one hour to travel 40 miles, then we don't have to scale or anything. We know $\frac{40 miles}{1 hr}$ , the answer is...

"It'll only take one hour to travel 40 miles. This is correct because the unit rate is $\frac{40 miles}{1 hr}$ . "

3. Knowing that the constant speed of the plane is $\frac{800 km}{1 hour\\}$ , we can scale then add half of the unit rate to get our answer.

$\frac{800 km}{1 hour\\}$ x 3 = $\frac{2400 km}{3 hrs}$ 800 x 3 = 2400

then add half of unit rate which is $\frac{400 km}{30 mins}$ $\sqrt[2]{800}$ = 400

so, our answer is $\frac{2800 km}{3.5 hours}$

4. $\frac{3km}{30 mins}$ <--- ( divided by 2) $\frac{6 km}{1 hr}$ ( multiplied x 2.5) ---> $\frac{15 km}{2.5 hrs}$

To get an easier way to find the answer, if possible you can scale back farther than the 1 hour mark.

Elmer would take 2 and a half hours to ride 15 km.

5. The boys speed is $\frac{4 km}{1 hr}$ . All we need to do is divide by 2. $\sqrt[2]{8}$ = 4

3 0

3 years ago

Create the Systems of inequality for the following scenario:

Lana71 [14]

Answer:

8 x + 25y ≥100

x+y ≤ 14

Step-by-step explanation:

Hi, to answer this question we to write a system of inequalities.

First inequality:

The product of the earnings per hour working at culvers (8) and the number of hours worked there, plus the product of the earnings per hour mowing lawns (8) and the number of hours mowing must be greater or equal to $100.

Second inequality:

The amount of time he works at culvers (x) plus the amount of time he works mowing lawn (y) must be less or equal to 14 hours.

8 x + 25y ≥100

x+y ≤ 14

Where:

x = number of hours worked at Culvers

y= number of hours worked Mowing lawns

8 0

3 years ago

3x^2+kx=-3 What is the value of K will result in exactly one solution to the equation?

Scorpion4ik [409]

Answer: