Find the missing side length of the right triangle

Mathematics

2 answers:

maksim [4K]3 years ago

6 0

Answer:

x=16

Step-by-step explanation:

<h2><u>This is an unidentified triangle or a scalene</u></h2><h2><u>The equation: 14^2+x^2=q^2 </u></h2><h2><u>This equation is for the pathagoern theorem. (If you have not learned it put a thanks and ask the question about it) </u></h2><h2><u>This equation 14^2+x^2=q^2 = 14^2=x^2-q^ = x^2= 32 = x = 16</u></h2><h2><u>I hope this helps!</u></h2>

fredd [130]3 years ago

3 0

Answer:

x=16

Step-by-step explanation:

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Answer:

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A box in a supply room contains 24 compact fluorescent lightbulbs, of which 8 are rated 13-watt, 9 are rated 18-watt, and 7 are

Marrrta [24]

Answer:

a) There is 17.64% probability that exactly two of the selected bulbs are rated 23-watt.

b) There is a 8.65% probability that all three of the bulbs have the same rating.

c) There is a 12.45% probability that one bulb of each type is selected.

Step-by-step explanation:

There are 24 compact fluorescent lightbulbs in the box, of which:

8 are rated 13-watt

9 are rated 18-watt

7 are rated 23-watt

(a) What is the probability that exactly two of the selected bulbs are rated 23-watt?

There are 7 rated 23-watt among 23. There are no replacements(so the denominators in the multiplication decrease). Then can be chosen in different orders, so we have to permutate.

It is a permutation of 3(bulbs selected) with 2(23-watt) and 1(13 or 18 watt) repetitions. So

$P = p^{3}_{2,1}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = \frac{3!}{2!1!}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 3*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 0.1764$