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VLD [36.1K]
2 years ago
7

Find the equation of the line that goes through the points (2, 2) and (6, 6).

Mathematics
2 answers:
atroni [7]2 years ago
7 0

Answer:

D

Step-by-step explanation:

y=6x+2

2=12+2

NO
y=-x

2=-2

NO

y=2x+6

2=4+10

NO

y=x

2=2

6=6

notka56 [123]2 years ago
3 0

Answer:

y=x

Step-by-step explanation:

We will use slope-intercept form:

y=mx+b

Where m=slope and b =y-intercept

To find the slope we use the slope formula:

\frac{y_2-y_1}{x_2-x_1}

We plug in the coordinates getting:

\frac{6-2}{6-2} =\frac{4}{4}  = 1

So we have a slope of 1:

y=(1)x+b

If we look at the answer choice we see that only one of them has a slope of 1 so the equation is:

y =x

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shepuryov [24]

Answer:

6.25 inches

Step-by-step explanation:

25/4=6.25

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3 years ago
Read 2 more answers
Evaluate the expression when r = 8.2 and s = –3.7.
kiruha [24]
When you plug in the numbers for the integers, you get
8.2-2(-3.7)
If you multiply -2 and -3.7, you get 7.4 because the negatives cancel each other out.
If you then add 8.2, you get 15.6. So the answer is D.
Hope it Helps!  :)
8 0
3 years ago
14. Sharon earns $25 per item she sells plus a base salary of $100 per week. Write and solve an inequality to find how many item
kozerog [31]
Amount earned by Sharon per item sold = $25
Base salary of Sharon per week = $100
Amount that needs to be earned by Sharon per week = $700
Let us assume the number of items sold by Sharon per week = x
Then
100 + 25x = 700
25x = 700 - 100
25x = 600
x = 600/25
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3 years ago
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3 years ago
An important tool in archeological research is radiocarbon dating, developed by the American chemist Willard F. Libby.3 This is
Radda [10]

Answer:

Q(t) = Q_o*e^(-0.000120968*t)

Step-by-step explanation:

Given:

- The ODE of the life of Carbon-14:

                                       Q' = -r*Q

- The initial conditions Q(0) = Q_o

- Carbon isotope reaches its half life in t = 5730 yrs

Find:

The expression for Q(t).

Solution:

- Assuming Q(t) satisfies:

                                       Q' = -r*Q

- Separate variables:

                                      dQ / Q = -r .dt

- Integrate both sides:

                                       Ln(Q) = -r*t + C

- Make the relation for Q:

                                       Q = C*e^(-r*t)

- Using initial conditions given:

                                       Q(0) = Q_o

                                       Q_o = C*e^(-r*0)

                                      C = Q_o    

- The relation is:

                                       Q(t) = Q_o*e^(-r*t)

- We are also given that the half life of carbon is t = 5730 years:

                                       Q_o / 2 = Q_o*e^(-5730*r)

                                        -Ln(0.5) = 5730*r

                                        r = -Ln(0.5)/5730

                                        r = 0.000120968          

- Hence, our expression for Q(t) would be:

                                       Q(t) = Q_o*e^(-0.000120968*t)                                    

7 0
3 years ago
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