The value of x in the equation is 26. 087
<h3>What are algebraic expressions?</h3>
Algebraic expressions are defined as expressions made up of terms, constants, coefficients, factors and variables.
They may also include certain mathematical or arithmetic operations which includes;
- Bracket
- Division
- Addition
- Subtraction
- Parentheses
- Multiplication and so on
Given the equation;
(0.020) (0.030) / (0.10)x = 2.3 × 10-4
We can simply the equation following the steps;
expand the brackets, we have;
6× 10^-4/ 0.10x = 2.3 × 10^-4
Now, cross multiply
0.10x × 2.3 × 10^-4 = 6× 10^-4
Divide both sides by 2.3 × 10^-4
0. 10x = 6× 10^-4/2.3 × 10^-4
Find the quotient
0. 10x = 2. 608
Let's make the variable 'x' by dividing both sides by it's coefficient
0. 10x/0.10 = 2. 608/0. 10
x = 26. 087
Hence, the value is 26. 087
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Answer:
The required point is P(-7,
) where, x-coordinate twice the y-coordinate on line 2x - 6y = 7
Step-by-step explanation:
Given equation of line is 2x-6y=7
To find point on graph whose x-coordinate twice the y-coordinate:
Let y be y-coordinate of point
Hence, x-coordinate of point will be 2y
The required point is P(2y,y) on equation of line 2x-6y=7
Now,
2x-6y=7
2(2y)-6y=7
-2y=7
y=
Thus,
The required point is P(-7,)
Note: Figure show equation of line red line and point P as blue dot.
Answer:
95
Step-by-step explanation:
you first find out the angles mn and mt.
Since ns and ms are the same, we know ms is 35 degrees.
mt is 50, so we subtract 50 and 35 from 180, which is the degree of m.
so the answer is 95 degrees.
Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
________________________________
now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
Answer:
You cannot do this because 2800 cm squared is area and liters is volume. however, if you mean 2800 cm cubed, then the answer is 2.8 liters.
Step-by-step explanation:
