When y is 4, p is 0. 5, and m is 2, x is 2. If x varies directly with the product of p and m and inversely with y, which equatio

Question

1 year ago

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When y is 4, p is 0. 5, and m is 2, x is 2. If x varies directly with the product of p and m and inversely with y, which equatio

n models the situation?
x p m y = 8
StartFraction x y Over p m EndFraction = 8
StartFraction x p m Over y EndFraction = 0. 5
StartFraction x Over p m y EndFraction = 0. 5

Mathematics

1 answer:

dmitriy555 [2] · Answer 1 · 2023-08-20T01:09:45+03:00

Answer:

$\dfrac{xy}{pm}=8$

Step-by-step explanation:

If x varies directly as the product of p and m, and inversely with y, the relation can be written ...

x = k(pm)/y . . . . where k is the constant of proportionality

__

This can be solved for k:

k = xy/pm

For the given values, the value of k is ...

k = (2)(4)/((0.5)(2)) = 8

Then the relation between the variables can be written ...

(xy)/(pm) = 8