Answer:
the Archaea, the Bacteria, and the Eukarya.
Explanation:
Answer:
First, we take the owl out, the total number of mouse increases at a higher rate and the chipmunks are also decreasing in numbers. In an ideal ecosystem, both mice (lets call it "a") and chipmunks (lets call it "b") should increase since the restraining factor has been removed. But that is the opposite of what we should see. In that case, we will take the owl to be the "limiting factor" for the rodents.
Am
The rodents will have free movement and exercise their fitness over the area, competition sets in between the two species. So we see, a flourishes while b dies out. This can be viewed most predictably that a has an overall greater fitness and would easily get resources and strive readily, which influences the survival rate for 2.
Hope you got something in any realm of understanding?
Answer:
The correct answer is option C. "2+".
Explanation:
A common procedure to test for the presence of antigens is to perform an agglutination reaction by performing an antibody screen. In an agglutination reaction that is graded 2+ the red blood cells start to be broken and medium-sized agglutinates are formed. In this reaction no red blood cells are free, only agglutinates are seen at the bottom of the microtubes. The characteristics of the reaction herein described concur with an agglutination reaction that is graded 2+.
By pushing on the top of it and the water or substance will get into it
Answer: B). CO₂
Cellular respiration is the process of conversion of food energy (glucose) into chemical energy (ATP). Oxygen and glucose are the reactants in the chemical reaction of this process and carbon dioxide and water are the products.