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3 years ago

Rearrange the formula P = 2(l + b) for b.

Mathematics

1 answer:

Elan Coil [88]3 years ago

6 0

B = -l + 1/2 P is the answer

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WARM-UP Solutions

Andreas93 [3]

Answer:

x = 2

Step-by-step explanation:

Rearrange terms

Subtract from both sides of the equation

Simplify

Divide both sides of the equation by the same term

Simplify

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6 0

3 years ago

Which is the equation in slope-intercept form for the line that passes through (3, 7)

quester [9]

Answer:

$y = - \frac{5}{3} x + 12$

Step-by-step explanation:

First, rewrite the given equation in the form of y=mx+c.

m is the gradient while c is the y-intercept.

3x-5y=8

5y= 3x -8

$y = \frac{3}{5} x - \frac{8}{5}$

Thus, the gradient of the given equation is ⅗.

The product of the gradients of perpendicular lines is -1.

(gradient of line)(⅗) = -1

gradient of line= -1 ÷⅗

gradient of line= $- \frac{5}{3}$

$y = - \frac{5}{3} x + c$

To find the value of c, substitute a coordinate.

When x=3, y=7,

$7 = - \frac{5}{3} (3) + c$

7= -5 +c

c= 7+5

c= 12

Hence, the equation of the line is $y = - \frac{5}{3} x + 12$ .

6 0

3 years ago

By hitting a target, Juanita can score 16, 17, 23, 26, 29 or 40 points with each arrow. What is the fewest arrows she can shoot

mezya [45]

Shoot two arrows worth 16 points each (32 points)

3 0

3 years ago

The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true

Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

Part A

$\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478$

Part B

$P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767$

Part C

$\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971$

6 0

2 years ago

Which of the following Triangle cases cannot be solved, using either the law of cosines or law of sines

hodyreva [135]

The answer is D. You cannot use aaa

8 0

3 years ago

Read 2 more answers