Question

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER

Answer 1

Answer:

$\sf \sin A=\boxed{\dfrac{5}{13}}\quad\cos A=\boxed{\dfrac{12}{13}}\quad\tan A=\boxed{\dfrac{5}{12}}$

Step-by-step explanation:

Trigonometric ratios

$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}$

where:

• $\theta$ is the angle
• O is the side opposite the angle
• A is the side adjacent the angle
• H is the hypotenuse

Given:

• $\theta$ = A
• O = BC = 5
• A = AC = 12
• H = AB = 13

$\implies \sf \sin A=\dfrac{5}{13}\quad\cos A=\dfrac{12}{13}\quad\tan A=\dfrac{5}{12}$