Answer:
The last 2 statements are true
Step-by-step explanation:
given f(x) = x² + 6x and g(x) = 2x³
f(x) × g(x) = 2x³(x² + 6x) = 2
+ 12
not 2 + 12x³
f(0) = 0 + 0 = 0 and g(2) = 2 × 2³ = 2 × 8 = 16
f(0 × g(0) = 0 × 16 = 0 ≠ 16
f(1) = 1 + 6 = 7 and g(1) = 2 × 1³ = 2
f(1) × g(1) = 7 × 2 = 14 ← True
g(x) × g(x) = 2x³ × 2x³ = 4
= 4
← True
Answer:
c-17=x>33
c=51
Step-by-step explanation:
For it to be a linear equation, the same difference in x must produce the same difference in y always.
Choice A.
difference in x: 2 - 1 = 1
difference in y: -6 - (-2) = -4
difference in x: 3 - 2 = 1
difference in y: -2 - (-6) = 4
A difference of 1 in x gave a difference of -4 in y and another difference of 1 in x gave a difference of 4 in y.
This is not linear.
Choice B.
difference in x: 2 - 1 = 1
difference in y: -5 - (-2) = -3
difference in x: 3 - 2 = 1
difference in y: -9 - (-5) = -4
A difference of 1 in x gave a difference of -3 in y and another difference of 1 in x gave a difference of -4 in y.
This is not linear.
Choice C.
difference in x: 2 - 1 = 1
difference in y: -10 - (-2) = -8
difference in x: 3 - 2 = 1
difference in y: -18 - (-10) = -8
Do the other differences. All differences in y are -8 corresponding to a difference in x of -1.
This is linear.
Choice D.
The differences in y vary. It is not linear.
Answer: Choice C is linear.
781 would be the answer I believe
