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MAXImum [283]
3 years ago
10

Please answer I need help with my I-ready

Mathematics
1 answer:
Rainbow [258]3 years ago
8 0

The answer is in the image

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Please help.<br> Is algebra.
Veronika [31]

Answer:

B

Step-by-step explanation:

The first one is a binomial. It has two different terms on either side of the middle minus sign. y is raised to the 4 th power so that is degree 4. The answer is b

The second problem is ordered as 4 3 1 2

The powers determine the degree. The terms are all different and the number of terms is determined by the powers of the letters in the terms.

3 0
3 years ago
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For which data set would the median be a better measure of center than the mean?
Montano1993 [528]

Answer:

I think D but I'm not 100 percent certain

7 0
3 years ago
Which tool would be best to solve this problem?
hjlf

Step-by-step explanation:

Cosine Ratio is the best tool to solve this problem.

cos38°=x/8

x =8*cos38°

x = 8*0.79

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5 0
3 years ago
Solve the following equation. Then place the correct number in the box provided.
zvonat [6]

Answer:

15

Step-by-step explanation:

\dfrac{2x}{5}+1=7

Subtract 1 from both sides:

\dfrac{2x}{5}=6

Multiply both sides by 5:

2x=30

Divide both sides by 2:

x=15

Hope this helps!

8 0
3 years ago
Find z 1 ÷ z 2 for z 1 = 9(cos225° + isin225°) and z 2 = 3(cos45° + isin45°).
olga nikolaevna [1]

\bf \qquad \textit{division of two complex numbers} \\\\ \cfrac{r_1[cos(\alpha)+isin(\alpha)]}{r_2[cos(\beta)+isin(\beta)]}\implies \cfrac{r_1}{r_2}[cos(\alpha - \beta)+isin(\alpha - \beta)] \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \begin{cases} z1=9[cos(225^o)+i~sin(225^o)]\\\\ z2=3[cos(45^o)+i~sin(45^o)] \end{cases}\implies \cfrac{z1}{z2}\implies \cfrac{9[cos(225^o)+i~sin(225^o)]}{3[cos(45^o)+i~sin(45^o)]} \\\\\\ \cfrac{9}{3}[cos(225^o-45^o)+isin(225^o-45^o)]\implies 3[cos(180^o)+i~sin(180^o)] \\\\\\ 3[(-1)+i~(0)]\implies -3+0i

8 0
4 years ago
Read 2 more answers
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