Answer: B and C
Hope this help :)
20mps. Because velocity is the speed per unit. In this case it is going 20 m per second
The given quadrilateral is a kite.
Given: Point A (2, 4), B (-2, -5), C (7, -1) and D (7, 4)
Firstly, we find the distance between AD and DC
AD =
⇒ AD =
⇒ AD = 5
DC =
⇒ DC =
⇒ DC = 5
Hence, AD = DC = 5
Now, find the distance between AB and BC
AB =
⇒ AB =
⇒ AB =
⇒ AB =
BC =
⇒ BC =
⇒ BC =
⇒ BC =
Hence, AB = BC = √97
In the given quadrilateral, the two pair is of equal length and these sides are adjacent to each other.
Hence, it follows the property of kite.
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Answer:
[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]
Step-by-step explanation:
x³+216y³+8z³-36xyz
x³+(6y)³+(2z)³-3×6×2×xyz
As we know
a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)
Let a=x
b=6y
c=2z
Now.
[x+6y+2z][(x²+(6y)²+(2z)²-x×6y-6y×2z-x×2z]
[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]