W=0
Z=-2
Is there a need for explanation?
Let the token profit be X.
For a win, the profit is 2 tokens.
For a loss, the profit is -3 tokens.
The probability of a win is
<span><span>212</span>+<span>212</span>+<span>212</span>=<span>612</span>=<span>12</span></span>
the probability of a loss is
<span><span>612</span>=<span>12</span></span>
Setting up a probability distribution variable gives:
<span>E(X)=(−3×<span>12</span>)+(2×<span>12</span>)=−1<span>12</span>+1=−<span>12</span> token</span><span>
Therefore, on average, the player would expect to lose a half a token per game.</span>
<h2>Answer:</h2><h2>-4</h2><h2 /><h2>Hope this helps!!</h2>
To solve this problem you must apply the proccedure shown below:
1. The area of the rectangle is:

Where
is the width and
is the length.
2. Based on the data given, solve for the width and then substitute the values of the length and the values of the area. Therefore, you have:

The answer is the second option:

Answer:
We need a sample size of at least 719
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?
This is at least n, in which n is found when
. So






Rouding up
We need a sample size of at least 719