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stealth61 [152]
2 years ago
11

Write an expression to represent a number squared, added to 5

Mathematics
2 answers:
vodomira [7]2 years ago
8 0

Answer:

x² + 5

Step-by-step explanation:

Given statement:

  • "number squared, added to 5"

<u>We know the following:</u>

    1. "number squared" ⇒ A number multiplied to the same number.

<em>     Let the number be known as "x". Then;</em>

<em>         </em>\implies x \times x

<em>        </em> \implies \underline{x^{2}}

   2. "added to 5" ⇒ Addition between number, squared and 5.

<em>    Let the number be known as "x". Then;</em>

        \implies (x)^{2}  + 5  (\text{number, squared} \implies x^{2} )

        \implies \boxed{x^{2}  + 5}

Therefore, the expression that represents the statement is x² + 5.

Gnom [1K]2 years ago
7 0

Answer: x^2+5

Step-by-step explanation:

x is the unknown variable which is representing the number squared and then you add 5 to complete expresssion.

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Step-by-step explanation:

Let the current display rate be f (in frames per second).  If the new computer is 40% faster, then the new display rate will be 1.40f (frames per second).

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3 years ago
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Anni [7]

Answer:

C. 6.8 in

Step-by-step explanation:

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3 years ago
what kind of growth model (pattern) is showen in the table x 1, 2, 3, 4, 5 y 5, 25, 125 ,635 ,3,125
Mandarinka [93]

Answer:

x= AP, y= GP

Step-by-step explanation:

x = 1, 2, 3, 4, 5 - difference in terms = 1, this is AP

y = 5, 25, 125, 625, 3125 - the ratio of increase= 5, this is GP

7 0
3 years ago
75% of blank peaches is 15 peaches?
satela [25.4K]

.75 * p = 15

divide by .75

p = 15/.75 = 20

20 peaches

.15 * d = puppies

.15 * 60 = puppies

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divide by .09

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4 0
4 years ago
For each function, y varies directly with x. Find each constant of variation. Then find the value of y when x=-0.3
Viktor [21]

<u><em>Answer:</em></u>

1- The constant of variation is \frac{10}{3}

2- The constant of variation is \frac{4}{3}

<u><em>Explanation:</em></u>

When two variables are in direct variation, this means that when one of them increases, the other increases and vice versa

<u>A direct variation relation is represented as follows:</u>

y = kx

where k is the constant of variation

Now, to get the constant of variation, all we have to do is substitute with the given x and y variables and solve for k

<u>For the given problems:</u>

<u>1- y = \frac{2}{3}\ when\ x=0.2</u>

<u>Therefore:</u>

y = kx\\\\\frac{2}{3} = 0.2k\\\\ k = \frac{10}{3}

<u>2- y = 4\ when\ x=3</u>

<u>Therefore:</u>

y = kx\\ 4 = 3k\\ k = \frac{4}{3}

Hope this helps :)

5 0
3 years ago
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