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2 years ago

What is the solution set for the inequality 4 - 5g > 39?

Mathematics

1 answer:

katrin [286]2 years ago

6 0

The solution set for the given inequality is $g > -7$

<u>Given the following inequality:</u>

$4 - 5g > 39$

<h3>What is an inequality?</h3>

An inequality can be defined as a mathematical relation that is typically used to compare two (2) integers or variables in an equation by illustrating any of the following:

Greater than (>).

Less than (<).

Greater than or equal to the other (≥).

Less than or equal to the other (≤).

Simplifying the inequality, we have:

$4 - 5g > 39\\\\5g > 4-39\\\\5g > -35\\\\g > -7$

Read more on inequality here: brainly.com/question/24372553

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katovenus [111]

Answer:

The option "StartFraction negative 2 (x + 6) Over (x + 4) (x minus 4) EndFraction" is correct

That is $\frac{-2(x+6)}{(x+4)(x-4)}$

Therefore $\frac{x}{x^2-16}-\frac{3}{x-4}=\frac{-2(x+6)}{(x+4)(x-4)}$

Step-by-step explanation:

Given problem is StartFraction x Over x squared minus 16 EndFraction minus StartFraction 3 Over x minus 4 EndFraction

It can be written as below :

$\frac{x}{x^2-16}-\frac{3}{x-4}$

To solve the given expression

$\frac{x}{x^2-16}-\frac{3}{x-4}$

$=\frac{x}{x^2-4^2}-\frac{3}{x-4}$

$=\frac{x}{(x+4)(x-4)}-\frac{3}{x-4}$ ( using the property $a^2-b^2=(a+b)(a-b)$ )

$=\frac{x-3(x+4)}{(x+4)(x-4)}$

$=\frac{x-3x-12}{(x+4)(x-4)}$ ( by using distributive property )

$=\frac{-2x-12}{(x+4)(x-4)}$

$=\frac{-2(x+6)}{(x+4)(x-4)}$

$\frac{x}{x^2-16}-\frac{3}{x-4}=\frac{-2(x+6)}{(x+4)(x-4)}$

Therefore $\frac{x}{x^2-16}-\frac{3}{x-4}=\frac{-2(x+6)}{(x+4)(x-4)}$

Therefore the option "StartFraction negative 2 (x + 6) Over (x + 4) (x minus 4) EndFraction" is correct

That is $\frac{-2(x+6)}{(x+4)(x-4)}$

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(7+11) is 18, (8/2) is 4, 18-4 is 14! If this expression is 6 less than her age, she would be 20!

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2 years ago

Can someone help! I know the answer I just need step by step!

baherus [9]

Answer:

$4 \sqrt{2}$

Step-by-step explanation:

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$\implies \sqrt{32}=\sqrt{16 \cdot 2$

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$\implies \sqrt{16 \cdot 2}=\sqrt{16}\sqrt{2}$

Rewrite 16 as 4²:

$\implies \sqrt{16}\sqrt{2}=\sqrt{4^2}\sqrt{2}$

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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substitute the values

$m=\frac{3-1}{0+3}$

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step 2

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substitute the values

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step 3

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therefore

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