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KIM [24]
2 years ago
5

the distribution of lengths of salmon from a certain river is approximately normal with standard deviation 3.5 inches. if 10 per

cent of salmon are longer than 30 inches, which of the following is closest to the mean of the distribution?
SAT
1 answer:
juin [17]2 years ago
3 0

Complete question;

<em>The distribution of lengths of salmon from a certain river is approximately normal with a standard deviation of 3.5 inches. If 10 percent of salmon are longer than 30 inches, which of the following is closest to the mean of the distribution? 26 inches A 28 inches B 30 inches C 33 inches D 34 inches</em>

Option B is correct. The value that is closest to the mean of the distribution is 30inches.

The formula for calculating the z-score is expressed as:

z=\frac{ x-\mu}{\sigma}

Given the following parameters

\sigma = 3.5\\x = 26in

If 10 percent of salmon are longer than 30 inches, then:

  • P(x>30) = 0.1

Using the z table to get the value corresponding to the mean area 0.1.

  • The required z-score will be -1.285

Substitute the resulting parameters into the formula to get the mean of the distribution.

z=\frac{x-\mu}{\sigma}\\-1.285=\frac{26-\mu}{3.5}\\-1.285 \times 3.5 = 26 - \mu\\ -4.4975 = 26 - \mu\\\mu = 26 + 4.4975\\\mu = 30.4975\\\mu \approx 30in

Hence the value that is closest to the mean of the distribution is 30inches.

Learn more here: brainly.com/question/15295437

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