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Likurg_2 [28]
3 years ago
8

Find the variable x in the figure if AB ll CD ll EF where c and d are the midpoints of AE and BF.

Mathematics
1 answer:
dangina [55]3 years ago
5 0
CD is called the middle base and is equal to :(AB + EF)/2

CD = <span>(AB + EF)/2

4x = [(x</span>²+10) + (8-x)]/2

8x = x²+10+8-x

8x= x²-x+18
x²-9x+18 = 0

x' = [-b+√(b²-4.a.c)]/2a       & x" = [-b-√(b<span>²-4.a.c)]/2a

x'= 6  and x" = 3, So we have2 values of x</span>
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Which expressions are equivalent to the one below? Check all that apply.<br> 3x
noname [10]

Answer:

F and C

Step-by-step explanation:

5 0
3 years ago
The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2885 and standard deviation
aliina [53]

Answer:

a.  X~N(2,885, 651)

b.  0.086291

c.  0.00058

d.  3213.10 calories

Step-by-step explanation:

a. -A normal distribution is expressed in the form X~N(mean, standard deviation).

-Let X a random variable denoting  the number of calories consumed.

-X is a is a normally distributed random variable with mean 2885 and standard deviation 651.

-This distribution is expressed as X~N(2,885, 651)

b. The probability that less than 2000 calories are consumed is calculated using the formula:

P(X

#substitute the given values in the formula to solve for P:

P(X

Hence, the probability of consuming less than 2000 calories is 0.08691

c. The proportion of customers consuming more than 5000 calories is calculated as:

P(X>x)=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(Z>\frac{5000-2885}{651})\\\\=P(z>3.2488)\\\\=1-0.99942\\\\=0.00058

Hence, the proportion of customers consuming over  5000 calories is 0.00058

d. The least amount of calories to get the award is calculated as:

1% is equivalent to a z value of 0.50399.

-We equate this to the formula to solve for the mean consumption:

0.01=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(z>\frac{\bar X-2885}{651})\\\\\1\%=0.50399 \\\\\frac{\bar X-2885}{651}=0.50399 \\\\\bar X=0.50399\times 651+2885\\\\=3213.09

Hence, the least amount of calories consumed to qualify for the award is 3213.10 calories.

8 0
3 years ago
What are the answers to ther two questions??
Vlad1618 [11]
the answer is the third option, starting with degree 11.
6 0
3 years ago
Read 2 more answers
The lsrl after an exponential transformation is log yhat=.4785 + 1.468x. What is the exponential form of the regression?
zheka24 [161]

Answer:

10^{0.4785+1.468x}=y

Step-by-step explanation:

So I'm assuming when you typed "log yhat=.4785 + 1.468x", you meant to write: log(y)=0.4785+1.468x. And generally a logarithm can be written in the form log_ba=c which can then be rewritten as b^c=a, but since the log has no base, it's assumed to be 10. So in this case you have the equation:

log_{10}y=0.4785+1.468x, which can then be written in exponential form as:

10^{0.4785+1.468x}=y

8 0
2 years ago
Can someone help me with a b and c please
abruzzese [7]

Answer:

c.in this 2014,396.12million pets were owned

3 0
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