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borishaifa [10]
2 years ago
15

Median of 1, 2, 3, 3, 4, 5, 6, 6, 6, 7

Mathematics
2 answers:
alukav5142 [94]2 years ago
6 0
The median is 4.5 as that is directly in the middle of 4 and 5, I think I’m right on that - hope it helps!
ludmilkaskok [199]2 years ago
3 0

Answer:

4.5

Step-by-step explanation:

the median is the middle number

You take the middle values, 4 and 5, and add them together. Then divide the sum of the values, 9, and then divide by 2.

Answer should be 4.5

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Step-by-step explanation:

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F(x)=x-1/x^2-x-6 which is the graph of
hoa [83]

Answer:

The graph is attached below.

Step-by-step explanation:

<em>As you have not added the graph, so I will be solving the function for a graph.</em>

Given the function

f\left(x\right)=x-\frac{1}{x^2}-x-6

x-\mathrm{axis\:interception\:points\:of\:}-\frac{1}{x^2}-6:

\mathrm{x-intercept\:is\:a\:point\:on\:the\:graph\:where\:}y=0

-\frac{1}{x^2}-6=0

-1-6x^2=0

\mathrm{No\:Solution\:for}\:x\in \mathbb{R}

\mathrm{No\:x-axis\:interception\:points}

y-\mathrm{axis\:interception\:point\:of\:}-\frac{1}{x^2}-6:

y\mathrm{-intercept\:is\:the\:point\:on\:the\:graph\:where\:}x=0

As we know that the domain of a function is the set of input or argument values for which the function is real and defined.

\mathrm{Domain\:of\:}\:-\frac{1}{x^2}-6\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x0\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:0\right)\cup \left(0,\:\infty \:\right)\end{bmatrix}

\mathrm{Since}\:x=0\:\mathrm{is\:not\:in\:domain}

\mathrm{No\:y-axis\:interception\:point}

\mathrm{Asymptotes\:of}\:-\frac{1}{x^2}-6:\quad \mathrm{Vertical}:\:x=0,\:\mathrm{Horizontal}:\:y=-6

\mathrm{Range\:of\:}-\frac{1}{x^2}-6:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)

The graph is attached below.

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D. divide 1000
hope this helped
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Deffense [45]
I found this for you. It even tells you how the answer was achieved.



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4 years ago
If the FBI breaks your door down and your innocent do they have to pay for it?
Elza [17]

Answer:

technically no but they should

Step-by-step explanation:

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