Question

A startled armadillo jumps straight into the air with an initial vertical velocity of 14ft / s . After how many seconds does it land on the ground? Use the equation - 16t ^ 2 + Vt + h . Round your answer to the nearest hundredth. The armadillo lands back on the ground after seconds.

Answer 1

Using the given equation, it is found that it lands on the ground after 0.875 seconds.

What is the equation for the projectile's height?

It is given by:

$h(t) = -16t^2 + vt + h$

In which:

• v is the initial velocity.

• h is the initial height.

In this problem, considering that the projectile jumps straight into the air with an initial vertical velocity of 14 ft/s, the parameters are v = 14 and h = 0, hence:

$h(t) = -16t^2 + 14t$

It lands on the ground when h(t) = 0, hence:

$-16t^2 + 14t = 0$

$t(-16t + 14) = 0$

Then:

$16t = 14$

$t = \frac{14}{16}$

$t = 0.875$

It lands on the ground after 0.875 seconds.

More can be learned about equations at brainly.com/question/25537936