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NARA [144]
2 years ago
10

Part 2. Show your work in solving the equation. Include the work to check your solution and show that your solution is extraneou

s. that has an extraneous solution. that does not have an extraneous solution. Part 3. Explain why the first equation has an extraneous solution and the second does not.
Mathematics
1 answer:
notsponge [240]2 years ago
8 0

Extraneous solutions are the values that we get when solving equations which aren't really solutions to the equation.

<h3>What are extraneous solutions?</h3>

Your information is incomplete. Therefore, an overview will be given.  An extraneous solution is the root of a transformed equation which is not a root of the original equation since it was excluded from the domain of the original equation.

The reason extraneous solutions exist is simply that some operations produce extra answers, and these operations are a part of the path to solving the problem.

Learn more about equations on:

brainly.com/question/2972832

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Whats the radius in the pic below for the school and gym locker??<br> Thanks
givi [52]
The school locker is 720 inches and the gym locker is 576 inches
5 0
3 years ago
I need help with this.
alekssr [168]

Answer:

x=7

Step-by-step explanation:

8 0
3 years ago
Explain why if a runner completes a 6.26.2​-mi race in 3434 ​min, then he must have been running at exactly 1010 ​mi/hr at least
iren [92.7K]

Answer:

All speed from 0 mi/h and 11 mi/h were reached because the initial and final speed was 0 mi/h the speed of 10 mi/hr was reached at least twice in the race.

Step-by-step explanation:

Given,

Total distance covered = 6.2 miles,

Time taken = 34 minutes = \frac{34}{60} hours

( 1 hour = 60 minutes )

Since,

Speed = \frac{Distance}{Time}

Thus, the speed of the runner = \frac{6.2}{\frac{34}{60}}

=\frac{6.2\times 60}{34}

=\frac{372}{34}

= 10.9411764706

≈ 11 miles per hour

Thus, the average speed of the runner is 11 miles per hour ( approx )

By MVT,

The speed was exactly 10 mi/hr at least twice in the race.

By intermediate value theorem,

All speed from 0 mi/h and 11 mi/h were reached because the initial and final speed was 0 mi/h the speed of 10 mi/hr was reached at least twice in the race.

4 0
3 years ago
f(x)=1x−2+4 and g(x)=1x+3+6 . Select from the drop-down menus to correctly complete the statement. You can get the graph of func
liubo4ka [24]

<em>You can get the graph of function g by taking the graph of function f and shifting it 7 units to the left, and by shifting it 7 units up.</em>

<h2>Explanation:</h2>

We have the following functions:

f(x)=1x-2+4 \\ \\ g(x)=1x+3+6

But we can rewrite this functions as:

f(x)=1x-2+4 \rightarrow f(x)=x+2 \\ \\ g(x)=1x+3+6 \rightarrow g(x)=x+9

Or:

g(x)=(x+2)+7

Recall that for vertical shifts:

h(x)=f(x)+k \\ \\ \bullet \ if \ k>0 \ f(x) \ is \ shifted \ k \ units \ up \\ \\ \bullet \ if \ k

From this, we know that:

  • <em>We can get g(x) by </em><em>shifting the graph of f(x) 7 units upward</em>

Recall that for horizontal shifts:

h(x)=f(x+k) \\ \\ \bullet \ if \ k>0 \ f(x) \ is \ shifted \ k \ units \ to \ the \ left \\ \\ \bullet \ if \ k

From this, we know that:

  • <em>We can get g(x) by </em><em>shifting the graph of f(x) 7 units to the left</em>

<em></em>

<h2>Learn more:</h2>

Shifting graphs: brainly.com/question/10010217

#LearnWithBrainly

6 0
3 years ago
Write the equation of a line which has a slope of 3 and passes through the point (1,5)
Arada [10]
Y=3x + 5

Y=mx + b
(m is the slope or gradient and b is the y intercept)
8 0
3 years ago
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