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vazorg [7]
2 years ago
10

Given OQ below, is YOR a minor arc, a major arc, or a semicircle?

Mathematics
1 answer:
Stells [14]2 years ago
8 0
C major arc more than half the circle
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Can someone help me with this please?
Karolina [17]
For the first image can you give us the choices for each one?
5 0
3 years ago
What is f(3) for the quadratic function<br>f(x)=2x2 + x – 12?<br>F -3<br>G 3<br>H 6<br>I. 9​
PolarNik [594]

Answer:

f(3) = 9

Step-by-step explanation:

Wherever you see an x on the right, put a 3 in for that x

f(x) = 2x^2 + x - 12

f(3) = 2*(3)^2 + 3 - 12

f(3) = 2*9 + 3 - 12

f(3) = 18 + 3 - 12

f(3) = 9

5 0
3 years ago
Whats the absolute vaule of -1 1/3​
Phoenix [80]

Answer:

1 1/3

Step-by-step explanation:

Absolute values are how far away it is from 0, so it is always positive. It is always the positive number of itself, so absolute values of negative numbers are the opposite, and the absolute value of positive numbers and just the same numbers.

5 0
4 years ago
Read 2 more answers
Given right triangle QRS, what is the value of sin(30°)? StartFraction StartRoot 3 EndRoot Over 3 EndFraction One-half StartFrac
baherus [9]

Answer:

Option 2: \sin(30)=\frac{1}{2}

Step-by-step explanation:

Given:

From the triangle shown below;

A triangle QRS with angle QRS = 90°, ∠QSR = 30°.

Side QR = 5, SQ = 10 and RS = 5√3

Now, we know from trigonometric ratio that,

\sin (A) = \frac{Opposite\ side}{Hypotenuse}

Here, opposite side of angle QSR is QR and Hypotenuse is the side opposite angle QRS which is SQ. Therefore,

\sin(\angle QSR)=\dfrac{QR}{SQ}\\\\\\\sin(30)=\dfrac{5}{10}\\\\\\\sin(30)=\dfrac{5}{2\times 5}=\dfrac{1}{2}

Therefore, the value of sine of 30° is one-half. So, second option is correct.

6 0
3 years ago
Read 2 more answers
50 points! I will mark brainliest! Random answers will be reported :)
ASHA 777 [7]

Answer:

x=10

Step-by-step explanation:

Notice that all three sides of the given triangle has one tick mark.

This means that all three sides are congruent, meaning that we have an equilateral triangle.

And for equilateral triangles, all three angles are also congruent.

So:

\angle CBA=\angle BAC=\angle ACB

Also, recall that the interior angles of a triangle is always 180. Thus:

\angle CBA+\angle BAC+\angle ACB=180

Substitute:

\angle CBA+\angle CBA+\angle CBA=180

Combine like terms:

3\angle CBA=180

Substitute:

3(6x)=180

Multiply:

18x=180

Thus:

x=10

And we are done!

3 0
3 years ago
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