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The stress experimented by the bungee cord due to Max's weight is approximately 299.680 kilopascals.
<h3>How to find the stress experimented by the bungee cord</h3>
Let suppose that the stress (), in pascals, experimented by the bungee cord is entirely <em>elastic </em>and <em>uniform</em>. By Newton's Laws we know that the tension (
), in newtons, experimented by the cord equals Max's weight. The stress on the bungee cord is axial and is described by following formula:
(1)
Where:
- Max's mass, in kilograms
- Gravitational acceleration, in meters per square second
- Diameter of the circular cross section, in meters
If we know that ,
and
, then the stress experimented by the bungee cord is:
The stress experimented by the bungee cord due to Max's weight is approximately 299.680 kilopascals.
To learn more on stress, we kindly invite to check this verified question: brainly.com/question/1178663
Based on the calculations, we have the following:
- The area of the sheet of paper is 96 square inches.
- The combined area of the triangle cutouts is equal to 36 square inches.
- The area of the parallelogram is equal to 60 square inches.
- The altitude of the parallelogram is equal to 6.51 square inches.
<u>Given the following data:</u>
- Dimension of paper = 12-inch by 8-inch.
Mathematically, the area of the paper is given by this formula:
Area = 96 square inches.
<u>For the four (4) right triangles:</u>
- Dimension 1 = 2 inches by 9 inches.
- Dimension 2 = 3 inches by 6 inches.
Therefore, the combined area of the triangle cutouts is given by:
This would be determined by subtracting the area of the four (4) right triangles from the areas of the paper as follows:
P = 60 square inches.
<h3>The altitude of the parallelogram.</h3>Altitude = 6.51 square inches.
Read more on parallelogram here: brainly.com/question/4459854
<u>Complete Question:</u>
A parallelogram is cut out of a 12-inch by 8-inch sheet of paper. There are four right triangle remnants. Two have the dimensions 2 inches by 9 inches, and the other two have the dimensions 3 inches by 6 inches. The resulting parallelogram has a base of approximately 9.22 inches.