Which expression is equivalent to (x^1/4y^16) ^1/2

You are driving from Show Low to Portland, Oregon. The trip will be 1,345 miles total. So

dusya [7]

$\huge \boxed{\mathfrak{Question} \downarrow}$

You are driving from Show Low to Portland, Oregon. The trip will be 1,345 miles total. So far, you have driven 3/5 of the way to Portland. How many miles do you have left to drive?

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

Miles to be driven in total = 1, 345 miles
Fraction of miles driven = 3/5
Fraction of miles left to be driven = 2/5 [5/5 - 3/5 = 2/5]
Miles left to be driven = ?

Now, let's solve it.

$\sf1345 \times \frac{2}{5} \\ \sf = \bcancel{1345} \times \frac{2}{ \bcancel{5}} \\ \sf = 269 \times 2 \\ = \boxed{ \boxed{ \bf \: 538}}$

So, the miles left to be driven by you is 538 miles.

6 0

3 years ago

On a coordinate plane, solid circles appear at the following points: (negative 4, 2), (negative 2, 2), (negative 1, 4), (1, 1),

Rainbow [258]

We need to remove either (1, 4) or (1, 1) to create a function.

<h3>How to alter a relation in order to obtain a function</h3>

Relations are formed by two sets, an input set known as domain and an output set known as range and relationships between these sets. A relation is a function if and only if each element from domain is related to only one element of the range. Mathematically speaking, we must satisfy the following proposition:

x → f(x), x → f'(x) ⇒ f(x) = f'(x)

Based on this definition, there are two possibilities to create a function:

Remove (1, 4)
Remove (1, 1)

To learn more on functions: brainly.com/question/12431044

#SPJ1

4 0

2 years ago

Priya and han plan a fundraiser for the running club.

Lilit [14]

Answer:a

Step-by-step explanation:

6 0

3 years ago

Two alloys A and B are being used to manufacture a certain steel product. An experiment needs to be designed to compare the two

sveta [45]

Answer:

Step-by-step explanation:

From the given information, we can compute the table showing the summarized statistics of the two alloys A & B:

Alloy A Alloy B

Sample mean $\bar {x} _A = 49.5$ $\bar {x} _B = 45.5$

Equal standard deviation $\sigma_A = 5$ $\sigma_B= 5$

Sample size $n_A = 30$ $n_{B}= 30$

Mean of the sampling distribution is :

$\mu_{\bar{X_1}-\bar{X_2}}= 49.5-45.5 \\ \\ = 4.0$

Standard deviation of sampling distribution:

$\sigma_{\bar{x_1}-\bar{x_2} }= \sqrt{\sigma^2_{\bar{x_1}-\bar{x_2} }} \\ \\ = \sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma^2_2}{n_2} } \\ \\ =\sqrt{\dfrac{25}{30}+\dfrac{25}{30}} \\\\=\sqrt{1.667} \\ \\ =1.2909$

Hypothesis testing.

Null hypothesis: $H_o: \mu_A -\mu_B = 0$

Alternative hypothesis: $H_A:\mu_A -\mu_B > 4$

The required probability is:

$P(\overline X_A - \overline X_B>4|\mu_A - \mu_B) = P\Big (\dfrac{(\overline X_A - \overline X_B)-\mu_{X_A-X_B}}{\sigma_{\overline x_A -\overline x_B}} > \dfrac{4 - \mu_{X_A-\overline X_B}}{\sigma _{\overline x_A - \overline X_B}} \Big) \\ \\ = P \Big( z > \dfrac{4-0}{1.2909}\Big) \\ \\ = P(z \ge 3.10)\\ \\ = 1 - P(z < 3.10) \\ \\ \text{Using EXCEL Function:} \\ \\ = 1 - [NORMDIST(3.10)] \\ \\ = 1- 0.999032 \\ \\ 0.000968 \\ \\ \simeq 0.0010$

This implies that a minimal chance of probability shows that the difference of 4 is not likely, provided that the two population means are the same.

b)

Since the P-value is very small which is lower than any level of significance.

Then, we reject $H_o$ and conclude that there is enough evidence to fully support alloy A.

3 0

3 years ago

Pls help for math homework. Show work.

vichka [17]

12x - 13 - x - 9 + 10x

First, get the like terms together

12x + 10x - x -13 -9

Now, combine like terms

12x + 10x - x = 21x

-13 - 9 = -22

Final Answer:

21x - 22

5 0

3 years ago