
<u>To</u><u> </u><u>find</u><u> </u><u>:</u><u>-</u>
The original number
<u>Given</u><u> </u><u>:</u><u>-</u>
The reverse of 2 digit number is 9 less than 3 times the original number
let tens digit of original number = x
ones digit = y
which means
(10y + x) + 9= 3(10x + y)
And the difference between the reverse digit and the original number is 45
(10y + x) - (10x + y) = 45
<u>Solution</u><u> </u><u>:</u><u>-</u>
(10y + x) + 9 = 3(10x + y) ---------- {equation 1}
10y + x + 9 = 30x + 3y
9 = 30x - x + 3y - 10y
9 = 29x - 7y ---------- {equation 2}
(10y + x) - (10x + y) = 45 ---------- {equation 3}
10y - y - 10x + x = 45
9y - 9x = 45 (dividing whole equation by 9)
y - x = 5
y = 5 + x ---------- {equation 4}
(putting values of equation 4 in equation 2)

(Putting the value of x in equation 4)
y = 5 + 2 = 7
<u>Verification</u><u> </u><u>:</u><u>-</u>
(Taking equation 3 and putting values of x and y)
(10y + x) - (10x + y) = 45
(10×7 + 2) - (10×2 + 7) = 45
(70 + 2) - (20 + 7) = 45
72 - 27 = 45
45 = 45
- <u>Hence</u><u>,</u><u> </u><u>verified</u><u>.</u><u> </u>
<u>Result</u><u> </u><u>:</u><u>-</u>
The original number is 27.