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Shtirlitz [24]
2 years ago
12

Mrs. o'brien used a compass to draw two circles on a coordinate plane. circle a is centered at (3,-1)

Mathematics
1 answer:
nata0808 [166]2 years ago
4 0

To prove that circle A is similar to circle B, it needs to be moved 1 unit right and 6 units up and then dilated by a scale factor of 3/4

<h3>What is transformation?</h3>

Transformation is the movement of a point from its initial location to a new location.

Types of transformation are <em>rotation, translation, dilation and reflection.</em>

<em />

To prove that circle A is similar to circle B, it needs to be moved 1 unit right and 6 units up and then dilated by a scale factor of 3/4

Find out more on transformation at: brainly.com/question/4057530

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What is the first step in solving the following equation?<br> 28 = -12 - 4x
alexgriva [62]

Answer:

<h3>4x = - 12 - 28</h3>

Step-by-step explanation:

When we transpose - 4x to the LHS then it becomes positive i.e +4x

Now we transpose 28 to the RHS then it becomes negative i.e - 28

So the first step you have to is,

<em>4x = - 12 - 28</em>

6 0
3 years ago
Solve for x ~<br><br><img src="https://tex.z-dn.net/?f=%5Cbold%5Cpink%7Bx%20%7B%7D%5E%7B2%7D%20%2B%205x%20-%206%20%3D%200%7D" id
Troyanec [42]

\qquad \qquad \rm \large \dag  \: Answer  \: \dag

We have been given a Quadratic equation, where we have to find the real values of x ~

So, let's proceed with middle term splitting method :

\qquad \sf  \dashrightarrow \:  {x}^{2}  + 5x - 6 = 0

\qquad \sf  \dashrightarrow \:  x {}^{2}  + 6x - x - 6 = 0

\qquad \sf  \dashrightarrow \:  {x(}^{} x + 6) - 1(x + 6) = 0

\qquad \sf  \dashrightarrow \: (x + 6)(x - 1) = 0

Now, we have two conditions here~

Either (x + 6) = 0

\qquad \sf  \dashrightarrow \: x =  - 6

or (x - 1) = 0

\qquad \sf  \dashrightarrow \: x = 1

4 0
2 years ago
CAN SOMEONE HELP ME WITH THIS PROBLEM????????????????????
Phantasy [73]

Answer:

<em>Hi there!</em>

<u><em>For 1. it should be answer b</em></u>

<u><em>For 2. it would be answer c</em></u>

<u><em>For 3. it is answer a</em></u>

<em>Hope I Helped!</em>

6 0
4 years ago
When Θ = 5 pi over 6, what are the reference angle and the sign values for sine, cosine, and tangent?
stira [4]
Note that (5π)/6 radians = 150°. Therefore the given angle is in quadrant 2.

Refer to the figure shown below.

Reference angles are measured relative to the horizontal axis.
Therefore the reference angle in each quadrant is π/6 radians or 30°.
Denote the reference angle as θ'.
Then, in quadrant 1,
cos θ' = √3/2,  sin θ' = 1/2,  tan θ' = √3.

Because we are in quadrant 2,
  sin θ' = π/6;
  sin(5π/6) is positive, but cos (5π/6) and tan (5π/6) are negative.

 Answer:
5π/6 is in quadrant 2.
The reference angle, θ' = π/6.
sin(5π/6) is positive, cosine and tangent are negative.

3 0
3 years ago
Read 2 more answers
Sixty-five percent of what number is 16.25?
Doss [256]

Answer:

25

Step-by-step explanation:

\frac{16.25}{x} = \frac{65}{100}

Cross Multiply

16.25 x 100 = 65x

1625 = 65x

1625 = \frac{65x}{65}

x = 25

6 0
3 years ago
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