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2 years ago

4.

1 answer:

8 0

The data given on the table about the ten participants in the health study shows that B. The post-run mean and median are the same value.

This can be found as:

= (87 + 95 + 96 + 101 + 110 + 104 + 100 + 101 + 90 + 96) / 10

= 98

<h3>What is the post run median?</h3>

First order the pulses from smallest to largest:

= 87, 90, 95, 96, 96, 100, 101, 101, 104, 110

The two digits in the middle are:

96 and 100

The median will be:

= (96 + 100) / 10

= 98

In conclusion, option B is correct.

Find out more on the median at brainly.com/question/396397.

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Please help me solve this question. Thank you

alekssr [168]

Answer:

There is no equation to answer

Step-by-step explanation:

4 0

3 years ago

The weight of a specific type of male monkey is normally distributed with a mean of 15 pounds and a standard deviation of 3 poun

Viktor [21]

Answer:

1.33

Step-by-step explanation:

The z-score of a value is found by subtracting the mean from the value and then dividing by the standard deviation, this is the formula for the z-score.

z-score = (19-15)/3

z-score = 4/3

z-score = 1.33

The z-score for the monkey is about 1.33

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3 years ago

Find the slope of the line that passes through the two<br> points.<br> (12, 15 ) and (5,7)

maria [59]

Slope of the line that passes through the two point is -2/7

6 0

3 years ago

Claim: The standard deviation of pulse rates of adult males is less than 11 bpm. For a random sample of 132 adult males, the pu

seraphim [82]

Answer:

$\chi^2 =\frac{132-1}{121} 114.49 =123.952$

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

$n=132$ represent the sample size

$\alpha$ represent the confidence level

$s^2 =10.7^2 =114.49$ represent the sample variance obtained

$\sigma^2_0 =11^2=121$ represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance specification is violated, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \geq 121$

Alternative hypothesis: $\sigma^2$

Calculate the statistic

For this test we can use the following statistic:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

$\chi^2 =\frac{132-1}{121} 114.49 =123.952$

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case 131. And since is a right tailed test the p value would be given by:

$p_v =P(\chi^2$

In order to find the p value we can use the following code in excel:

"=1-CHISQ.DIST(123.952,131,TRUE)"

5 0

3 years ago

LaVant takes a survey of his class and finds that 1/5 of his classmates watch the same show on friday night. If there are 480 st

atroni [7]

Answer:

Answer C: 96 students

Step-by-step explanation:

Take 1/5 of the 480 total students:

(1/5)(480) = 480/5 = 96

Answer C (96 students) is correct.

4 0

3 years ago