Answer:
Step-by-step explanation:
125 = 5 *5 * 5 = 5³
8 = 2 * 2 *2 = 2³
125x⁶ - 8 = 5³(x²)³ - 2³
= (5x²)³ - 2³ { a³ - b³ = (a -b)(a² + ab + b²)
= (5x² - 2) ([5x²]² + 5x²*2 + 2²)
= (5x² - 2)(25x⁴ + 10x² + 4)
Hint: (5x²)² = 5² * (x²)² = 25* x²ˣ² = 25x⁴
-2x·-2x·(-5x·-5x+4x·4x·4x) Basically, you write out the number depending on the exponent. So if you have a power/exponent of 3, you write it out multiplied by itself 3 times. Hope this helps!
B=3; C=16; and E=4096.
Using the information we have gives us

We know that:

We know that 2³ = 8, so B = 3.
To "undo" a square root, we square the number; 4²=16, so C = 16.
To "undo" a fourth root, we raise the answer to the fourth power; 8⁴ = 4096, so E = 4096.
I got the answer to be 42.