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Elenna [48]
2 years ago
8

Choose any literature that you want to interpret. It could be a song, movie, novel, K-Drama series, anime, manga, poem, and the

like. Then follow the DAIA (steps in literary criticism - check the picture) for your output. Use the attached paper for your answer. Check the sample for more information.
P.S. See the sample below.

NOTE: Plagiarism is a NO-NO. Plagiarized outputs will be automatically marked 0/20


​

English
1 answer:
sattari [20]2 years ago
8 0

The chosen literature we will analyze using the DAIA steps is a novel by F. Scott Fitzgerald called "The Great Gatsby," as is further explained below.

<h3>Using the DAIA steps</h3>

To ue the DAIA steps means we must describe the literature we have chosen, analyze a part of it and interpret it. Finally, we give it our own rating. Our chosen literature is "The Great Gatsby."

The DAIA steps about it are as follows:

  • Describe - "The Great Gatsby" is a novel by American author F. Scott Fitzgerald. It is about Jay Gatsby, a mysterious millionaire.
  • Analyze - One of Gatsby's most prominent characteristics is that he is a dreamer, always reaching for something he does not possess.
  • Interpret - That is what the green light means in the novel. It represents Gatsby's unattainable dream of being with Daisy.
  • Assess - We can rate this metaphor of the green light a 10 out of 10.

Learn more about "The Great Gatsby" here:

brainly.com/question/25865640

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Xelga [282]

★ Formula Applied :

\begin{gathered}\sf \bullet\ \; cos^2x-sin^2x=cos2x\\\\\to\ \sf \pink{sin^2x-cos^2x=-cos2x}\end{gathered}

\begin{gathered}\bullet\ \; \sf sin2x=2.sinx.cosx\\\\\to \sf \blue{sinx.cosx=\dfrac{sin2x}{2}}\end{gathered}

\displaystyle \bullet\ \; \sf \int \dfrac{dx}{x}

\bullet\ \; \sf \ln (ab)=\ln a+\ln

★ Explanation :

\begin{gathered}\displaystyle \sf \int \dfrac{sin^2x-cos^2x}{sinx.cosx}dx\\\\\to \sf \int \dfrac{-cos2x}{\frac{sin2x}{2}}dx\\\\\to \sf \int \dfrac{-2cos2x}{sin2x}dx\end{gathered}

Lets use substitution method ,

Let , u = sin2x

⇒ du = 2.cos2x.dx

\begin{gathered}\to \displaystyle \sf \int \dfrac{-du}{u}\\\\\to \sf -\int \dfrac{du}{u}\\\\\to \sf -ln|u|\\\\\end{gathered}

\to \sf \red{-ln|sin2x|+c}

\to \sf - \ln |2sinx.cosx|+c

\to \sf - \ln |sinx.cosx|+(\ln 2+c)

\leadsto - \sf \red{\ln |sinx.cosx|+c}\ \; \bigstar

★ Alternate Method :

\displaystyle \sf \int \dfrac{sin^2x-cos^2x}{sinx.cosx}

\displaystyle \to \sf \int \left( \dfrac{sin^2x}{sinx.cosx}-\dfrac{cos^2x}{sinx.cosx}\right)dx

\begin{gathered}\displaystyle \to \sf \int \left( \dfrac{sinx}{cosx} -\dfrac{cosx}{sinx} \right)dx\\\\\to\ \sf \int (tanx-cotx)dx\\\\\to \sf \int tanx.dx-\int cotx.dx\\\\\to \sf ln|secx|-ln|sinx|+c\end{gathered}

\to \sf ln\left| \dfrac{secx}{sinx}\right|+c

\begin{gathered}\to \sf ln\left| \dfrac{1}{sinx.cosx} \right|+c\\\\\end{gathered}]

\leadsto \sf \pink{-ln|sinx.cosx|+c}\ \; \bigstar

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<h3>~</h3>

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