Normalizing the bounds,
y=186, z = (186-200)/12 = -1.17
y = 210, z = (210 - 200)/12 = 0.83
We want the area of the standard normal between those. Looking it up in the cumulative table,
Ф(1.17) = 0.87900
Ф(0.83) = 0.79673
We need Ф(-1.17) which is 1 - Ф(1.17)
Then the probability we seek is
p = Ф(0.83) - Ф(-1.17) = Ф(0.83) + Ф(1.17) - 1 = 0.87900 + 0.79673 - 1 = 0.67573
Answer: 67.6%
Answer:
=2.4 cm
Step-by-step explanation:
In similar plane figures, the ratio of corresponding sides is a constant.
This constant is the linear scale factor.
In the provided example, 1.2cm corresponds to 0.96 while 3.0 corresponds to x
Thus, 1.2 cm/0.96 cm=3.0 cm/x
x=(3.0 cm×0.96 cm)/1.2 cm
=2.4 cm.
Answer:
Step-by-step explanation:
Add and subtract the square of half the x-coefficient:
x² -10x +(-5)² -(-5)² +15
Express the first three terms as a square; simplify the remaining terms.
(x -5)² -10
This expression describes a parabola that opens upward and has its vertex at (x, y) = (5, -10). The minimum value is -10.