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Olegator [25]
2 years ago
15

Find the variance of the following data. Round your answer to one decimal place. x 1 2 3 4 5 P(X=x) 0.3 0.2 0.2 0.1 0.2

Mathematics
1 answer:
Reptile [31]2 years ago
4 0

The variance of a distribution is the square of the standard deviation

The variance of the data is 2.2

<h3>How to calculate the variance</h3>

Start by calculating the expected value using:

E(x) = \sum x* P(x)

So, we have:

E(x) = 1 * 0.3 + 2* 0.2 +3 * 0.2 + 4 * 0.1 + 5 * 0.2

This gives

E(x) = 2.7

Next, calculate E(x^2) using:

E(x^2) = \sum x^2* P(x)

So, we have:

E(x^2) = 1^2 * 0.3 + 2^2* 0.2 +3^2 * 0.2 + 4^2 * 0.1 + 5^2 * 0.2

E(x^2) = 9.5

The variance is then calculated as:

Var(x) = E(x^2) - (E(x))^2

So, we have:

Var(x) = 9.5 - 2.7^2

Var(x) = 2.21

Approximate

Var(x) = 2.2

Hence, the variance of the data is 2.2

Read more about variance at:

brainly.com/question/15858152

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The one in the table on the left

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Answer:

36.58% probability that one of the devices fail

Step-by-step explanation:

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Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

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This means that n = 15

Assume that each device has a probability of 0.05 of failure during the course of the monitoring period.

This means that p = 0.05

What is the probability that one of the devices fail?

This is P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

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3 years ago
How much interest would be earned on $3,700 in one year if it is invested at 4%?
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Then you multiply $3,700•0.04 = $148

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