Answer:
Step-by-step explanation:
in tri ADC and tri BDC
∠ADC =∠BDC = 90
DC is common
AD = BD (given)
triangle ADC ≅ tri BDC by SAS congruency
hence AC = BC by CPCT ( congruent parts of congruent triangles)
hence, BC = 13
-6 belongs to a set of real numbers and also a set of rational numbers.
Real numbers are all integers: positive and negative whole numbers. So -6 is a real number.
Rational numbers are all numbers that can be expressed as a fraction i.e numerator/denominator form. So -6 = -6/1 which is a rational number.
(x+3y) (x-3y) = x^2 9y^2
(x-y) (x+3y) = x^2+2xy-3y^2
(xy+9y+2) (xy-3) = x^2 y^2 +9xy^2-xy-27y-6
(x^2+3xy-2) ( xy+3) = x^3 y+3x^2 y^2 +7xy-6
(2xy+x+y) (3xy^2-y) = 6x^2 y^3 +3x^2 y^2 +xy^2-2xy^2-xy-y^2
(xy+3x+2) ( xy-9) = x^2 y^2 +3x^2 y -7xy-27x-18
|-6 + 2| + |-11|
|4| + |-11|
= 15
Hope i helped!
<h3>
Answer: Choice B) 13</h3>
You chose the correct answer.
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Explanation:
Lines M and L are only parallel if and only if the corresponding angles are congruent.
The angles 127 and (9x+10) degrees are corresponding angles. They are both on the same side of the transversal, and they are to the right of each parallel line.
Set the two angle expressions equal to one another. Solve for x
9x+10 = 127
9x = 127-10
9x = 117
x = 117/9
x = 13
