Dr. Oguz counted the number of cubs in 10 tiger cub litters and then arranged the numbers from smallest to largest. The numbers
1 answer:
The relationship between the mean and MAD is used. Then the mean absolute deviation (MAD) is 0.
<h3>What is the mean absolute deviation?</h3>It is the average distance between each data point and the mean.
Dr. Oguz counted the number of cubs in 10 tiger cub litters and then arranged the numbers from smallest to largest.
The numbers of cubs in each litter were 1, 1, 2, 2, 3, 3, 3, 4, 5, and 6.
The mean of these measurements is 3.
The mean absolute deviation (MAD) is given by
N be the number of observation
μ be the mean
The mean absolute deviation (MAD) is 0.
More about the mean absolute deviation link is given below.
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The equation of line is y = 92x – 182631. The slope is 92 and the y-intercept is the negative 182631. And the health expenditure in 2010 will be 2289.
<h3>What is the equation of a line passing through two points?</h3>Suppose the given points are (x₁, y₁) and (x₂, y₂), then the equation of the straight line joining both two points is given by
In MODE, (second line), fix the number of decimal places to be 2.
Then the slope and the y-intercept values of the Lin Reg line will round to the nearest hundredth.
(x₁, y₁) → (1997, 1093)
(x₂, y₂) → (2002, 1553)
Then we have
y – 1093 = [(1553 – 1093) / (2002 – 1997)] (x – 1997)
y – 1093 = [460 / 5] (x – 1997)
y – 1093 = 92 (x – 1997)
y = 92x – 182631
If x = 2010, then the value of y will be
y = 92 × 2010 – 182631
y = 184920 – 192631
y = 2289
Learn more about straight-line equations here:
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Answer:
a) point estimate is 30%
b) null and alternative hypothesis would be
: p=27%
: p>27%
c) We reject the null hypothesis, percentage working people aged 65-69 had increased
Step-by-step explanation:
<em>a. </em>
Point estimate would be the proportion of the working people aged 65–69 to the sample size and equals ie 30%
<em>b.</em>
Let p be the proportion of people aged 65–69 who is working. OECD claims that percentage working had increased. Then null and alternative hypothesis would be
: p=27%
: p>27%
<em>c.</em>
z-score of the sample proportion assuming null hypothesis is:
where
- p(s) is the sample proportion of working people aged 65–69 (0.3)
- p is the proportion assumed under null hypothesis. (0.27)
- N is the sample size (600)
then z= = 1.655
Since one tailed p value of 1.655 = 0.048 < 0.05, sample proportion is significantly different than the proportion assumed in null hypothesis. Therefore we reject the null hypothesis.