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uysha [10]
2 years ago
12

How much force does the atmosphere exert on one side of a vertical wall 4. 00-m high and 10. 0-m long?

Mathematics
1 answer:
serious [3.7K]2 years ago
4 0

A force of 4.05×10⁶ N was exerted on one side of the wall.

<h3>What is the force?</h3>

Force is an external agent capable of changing the state of rest or motion of a particular body. It has a magnitude and a direction.

The following data were obtained from the question:

Breadth (B) = 4 m

Length (L) = 10 m

Standard pressure (P) = 101325 Nm¯²

Next, we shall determine the area of the wall. This can be obtained as follow:

Area (A) = length (L) × breadth (B)

A = 10 × 4

A = 40 m²

Finally, we shall determine the force exerted on one side of the wall as follow:

Standard pressure (P) = 101325 Nm¯²

Area (A) = 40 m²

Pressure (P) = Force (F) /Area (A)

101325 = F/40

F = 101325 × 40

F = 4.05×10⁶ N.

Therefore, a force of 4.05×10⁶ N was exerted on one side of the wall.

Learn more about force here;

brainly.com/question/17718499

#SPJ4

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A survey of 85 families showed that 36 owned at least one DVD player. Find the 99% confidence interval estimate of the true prop
attashe74 [19]

Answer:

0.424 - 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.286

0.424 + 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.562

The 99% confidence interval would be given by (0.286;0.562)

Step-by-step explanation:

Information given:

X= 36 represent the families owned at least one DVD player

n= 85 represent the total number of families

\hat p=\frac{36}{85}= 0.424 represent the estimated proportion of families owned at least one DVD player

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.05. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.424 - 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.286

0.424 + 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.562

The 99% confidence interval would be given by (0.286;0.562)

8 0
3 years ago
A Game Center has a $5 admission fee and charges $0.50 for each game played. Write an equation that represents the cost, C, in d
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Answer: $0.50c+$5=n Jensen
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3 years ago
Please help I don't understand this
vichka [17]

Answer:

First equation: No solution

Second Equation: One solution

Third equation: Infinitely many solutions

Step-by-step explanation:

Hope this helped, Have a Great Day!!

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Change each mixed number into an improper fraction 4 7/8​
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Answer:

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Step-by-step explanation:

Multiply the denominator by the whole number

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Add the answer from Step 1 to the numerator

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Write answer from Step 2 over the denominator

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