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Liono4ka [1.6K]
1 year ago
5

The spinner below is spun 60 times. Results are shown in the table below.

Mathematics
1 answer:
mezya [45]1 year ago
8 0

Answer:

Step-by-step explanation:

Theortical probability

A = 1/4

B = 1/3

C = 5/12

Experamental probability

A = 18/60 = 3/10

B = 20/60 = 1/3

C =  22/60 = 11/30

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10(a-2.5+0.56b) is this equivalent to 10a - 25+56b
kirill115 [55]

Hey there!

10(a - 2.5 + 0.56b)

= 10(a) + 10(-2.5) + 10(0.56b)

= 10a - 25 + 5.6b

= 10a + 5.6b - 25

Therefore, your answer is: 10a + 5.6b - 25

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

3 0
2 years ago
RAMP<br> 21.7 ft<br> 8.5 ft<br> 12 ft<br> 20 ft<br> 1. What is the total surface area of the ramp?
castortr0y [4]

Answer:

772.4 ft^2

Step-by-step explanation:

find the area of each face. first the slanted rectangle. the dimensions of the slanted rectangle are 21.7ft by 12ft. so the area is 21.7*12=260.4ft^2. for the two triangles on the sides, each on has an area of 20*8.5/2=85. next for the smaller rectangle, the dimensions are 12ft by 8.5ft giving us an area of 102 ft^2. lastly for the base, it has dimensions of 20ft by 12ft giving us an area of 240ft^2. now you just add up all the areas: 260.4+85+85+102+240=772.4 (you might want to check my addition just in case)

3 0
2 years ago
Read 2 more answers
Suppose brine containing 0.2 kg of salt per liter runs into a tank initially filled with 500 L of water containing 5 kg of salt.
Oliga [24]

Answer:

(a) 0.288 kg/liter

(b) 0.061408 kg/liter

Step-by-step explanation:

(a) The mass of salt entering the tank per minute, x = 0.2 kg/L × 5 L/minute = 1 kg/minute

The mass of salt exiting the tank per minute = 5 × (5 + x)/500

The increase per minute, Δ/dt, in the mass of salt in the tank is given as follows;

Δ/dt = x - 5 × (5 + x)/500

The increase, in mass, Δ, after an increase in time, dt, is therefore;

Δ = (x - 5 × (5 + x)/500)·dt

Integrating with a graphing calculator, with limits 0, 10, gives;

Δ = (99·x - 5)/10

Substituting x = 1 gives

(99 × 1 - 5)/10 = 9.4 kg

The concentration of the salt and water in the tank after 10 minutes = (Initial mass of salt in the tank + Increase in the mass of the salt in the tank)/(Volume of the tank)

∴ The concentration of the salt and water in the tank after 10 minutes =  (5 + 9.4)/500 = (14.4)/500 = 0.288

The concentration of the salt and water in the tank after 10 minutes = 0.288 kg/liter

(b) With the added leak, we now have;

Δ/dt = x - 6 × (14.4 + x)/500

Δ = x - 6 × (14.4 + x)/500·dt

Integrating with a graphing calculator, with limits 0, 20, gives;

Δ = 19.76·x -3.456 = 16.304

Where x = 1

The increase in mass after an increase in = 16.304 kg

The total mass = 16.304 + 14.4 = 30.704 kg

The concentration of the salt in the tank then becomes;

Concentration = 30.704/500 = 0.061408 kg/liter.

6 0
3 years ago
PLEASE ANSWER ASAP!!! I HAVE 2 HRS!!!
garik1379 [7]

Answer:

C

Step-by-step explanation:

6 0
2 years ago
PLEASE HELP ME!!!!!!
Harrizon [31]
65-26
A = 200(1+(0.0275/12)^0.0275(12 x 41 ) graph this in y =
7 0
3 years ago
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