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Elanso [62]
2 years ago
6

Find the measure of arc db. circle a is intersected by line cd at points d and e and line cb at point b, forming angle ecb outsi

de of the circle, the measure of angle ecb is 5x degrees, arc eb is 96 degrees, and arc db 25x plus 21 degrees. 25° 96° 118° 146°
SAT
2 answers:
Nonamiya [84]2 years ago
4 0

Answer:

The answer to this question is in fact 146 or answer "D."

Explanation:

Big brain energy

SVEN [57.7K]2 years ago
3 0

Answer:

146°

Steps:

FLVS

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company manufactured six television sets on a given day, and these TV sets were inspected for being good or defective. The resul
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Sampling distribution involves the proportions of a data element in a given sample.

  • <em>The proportion of Good TV set is 0.67</em>
  • <em>The number of ways of selecting 5 from 6 TV sets is 6</em>
  • <em>The number of ways of selecting 4 from 6 TV sets is 15</em>

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Given

n = 6

Sample Space = Good, Good, Defective, Defective, Good, Good

<u>(a) Proportion that are good</u>

From the sample space, we have:

Good = 4

So, the proportion (p) that are good are:

p = \frac{Good}{n}

p = \frac{4}{6}

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This is calculated using:

^nC_r = \frac{n!}{(n - r)!r!}

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r = 5

So, we have:

^6C_5 = \frac{6!}{(6 - 5)!5!}

^6C_5 = \frac{6!}{1!5!}

^6C_5 = \frac{6 \times 5!}{1 \times 5!}

^6C_5 = \frac{6}{1}

^6C_5 = 6

Hence, there are 6 ways

<u>(c) All possible sample space of 4</u>

First, we calculate the number of ways to select 4.

This is calculated using:

^nC_r = \frac{n!}{(n - r)!r!}

Where

r = 4

So, we have:

^6C_4 = \frac{6!}{(6 - 4)!4!}

^6C_4 = \frac{6!}{2!4!}

^6C_4 = \frac{6 \times 5 \times 4}{2 \times 1 \times 4!}

^6C_4 = \frac{30}{2}

^6C_4 = 15

So, the table is as follows:

\left[\begin{array}{ccc}TV&Good&Proportion\\1,2,3,4&2&0.5&2,3,4,5&2&0.5&3,4,5,6&2&0.5\\4,5,6,1&3&0.75&5,6,1,2&4&1&6,1,2,3&3&0.75\\1,2,3,5&3&0.75&3,5,6,2&3&0.75&1,3,4,5&2&0.5\\1,3,4,6&2&0.5&1,4,5,2&3&0.75&2,4,6,1&3&0.75\\2,4,6,3&2&0.5&2,4,6,5&3&0.75&3,5,6,1&3&0.75\end{array}\right]

The proportion column is calculated by dividing the number of Good TVs by the total selected (4) i.e.

p = \frac{Good}{n}

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In (a), we have:

p = 0.67 --- proportion of Good TV

The sampling error is calculated as follows:

SE_n = |p - p_n|

So, we have:

\left[\begin{array}{ccc}TV&Good&SE\\1,2,3,4&2&0.17&2,3,4,5&2&0.17&3,4,5,6&2&0.17\\4,5,6,1&3&0.08&5,6,1,2&4&0.33&6,1,2,3&3&0.08\\1,2,3,5&3&0.08&3,5,6,2&3&0.08&1,3,4,5&2&0.17\\1,3,4,6&2&0.17&1,4,5,2&3&0.08&2,4,6,1&3&0.08\\2,4,6,3&2&0.17&2,4,6,5&3&0.08&3,5,6,1&3&0.08\end{array}\right]

Read more about sampling distributions at:

brainly.com/question/10554762

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