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Nadusha1986 [10]
2 years ago
9

" title=" \textbf{Can someone help me with this question ?} " alt=" \textbf{Can someone help me with this question ?} " align="absmiddle" class="latex-formula">
\texttt{Note : you have to use vector method,} \texttt{no use determinants, or Area of Triangle = 0}

\textsf{If points with given position vectors are} \textsf{collinear then find the value of " a "}

\qquad \sf{\vec{A} = 60 \hat{i} + 3\hat{j} }

\qquad \sf{\vec{B} = 40 \hat{i} - 8\hat{j} }

\qquad \sf{\vec{C} = a\hat{i} - 52\hat{j} }

​
Mathematics
1 answer:
ale4655 [162]2 years ago
8 0

Answer:

here we go dude sorry for dirty handwriting

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y^{-8} y^3 x^0 x^{-2} is equivalent to y ^{-5} x ^{-2}\\.

<h3>What is a simplification of an expression?</h3>

Usually, simplification involves proceeding with the pending operations in the expression.

Simplification usually involves making the expression simple and easy to use later.

Given;

y^{-8} y^3 x^0 x^{-2}

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y^{-8} y^3 x^0 x^{-2}\\\\y ^{-8+3} x ^{0-2}\\ \\y ^{-5} x ^{-2}\\

Hence, y^{-8} y^3 x^0 x^{-2} is equivalent to y ^{-5} x ^{-2}\\.

Learn more about an expression here:

brainly.com/question/1249625

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