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Zina [86]
1 year ago
5

An arithmetic sequence has a1 = 22 and a8 = 43. Find a15.

Mathematics
1 answer:
brilliants [131]1 year ago
4 0

The 15th term of the arithmetic sequence a_{15} = 64

Option B is correct

The nth term of an arithmetic sequence is given as:

a_{n} = a + (n - 1)d

The first value, a = 22

a_8 = a+(8 - 1)d\\a_8 = a + 7d

Since a_8 = 43

43 = 22 + 7d\\7d = 43 - 22\\7d = 21\\d = \frac{21}{7}\\d = 3

The common difference, d = 3

a_{15}= a + (15-1)d\\a_{15} = a + 14d\\a_{15} = 22 + 14(3)\\a_{15} = 22 + 42\\a_{15} = 64

The 15th term of the arithmetic sequence = 64

Learn more here: brainly.com/question/24072079

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\displaystyle Range: Set-Builder\:Notation → [y|-2 ≤ y] \\ Interval\:Notation → [-2, ∞) \\ \\ Domain: Set-Builder\:Notation → [x|-4 ≤ x] \\ Interval\:Notation → [-4, ∞)

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