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LekaFEV [45]
4 years ago
15

Find the length of GF.

Mathematics
2 answers:
max2010maxim [7]4 years ago
7 0

Answer: t3 degrees top 90 bottom right 37 bottom left 5 line segment gf

Step-by-step explanation:

Mila [183]4 years ago
3 0

Answer:

t3 degrees top 90 bottom right 37 bottom left 5 line segment gf

Step-by-step explanation:

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Which of the following numbers can be expressed as decimals that terminate? 5 over 2, 4 over 5, 2 over 7, 4 over 3
Brilliant_brown [7]

Answer:

5/2, 4/5 are terminating decimals

Step-by-step explanation:

5/2 = 2.5  this is a terminating decimal

4/5 = .8 this is a terminating decimal

2/7 = .285714(repeating)  This is a repeating decimal

4/3 = 1.3(repeating)  this is a repeating decimal

5 0
3 years ago
Read 2 more answers
James has a balance of $1700 on a credit card with an APR of 18.7%, compounded monthly. About how much will he save in interest
miss Akunina [59]

Answer:

  $121.51

Step-by-step explanation:

At 18.7%, the monthly multiplier is 1+.187/12, so for the year, James' balance is multiplied by (1+.187/12)^12 ≈ 1.2038899

At 12.5%, the monthly multiplier is 1+.125/12, so for the year, James' balance is multiplied by (1+.125/12)^12 ≈ 1.1324161

The difference in these multipliers is ...

  1.2038899 -1.13241605 = 0.0714739

so James' savings is ...

  $1700 × 0.0714739 ≈ $121.51

5 0
3 years ago
Consider the leading term of the polynomial function. What is the end behavior of the graph? Describe the end behavior and provi
Nookie1986 [14]
The leading term is -3x^5.  The end behavior of any function is the behavior that the highest powered term has as x approaches ±oo.

In this case because the highest order term is -3x^5, as x approaches -oo, y approaches +oo.  And as x approaches +oo, y approaches -oo.
8 0
3 years ago
Which expression has the largest value? Each has
alukav5142 [94]

It's A. 9/2×3/8

I used a calculator

3 0
3 years ago
The u.s. department of health and human services collected sample data for 772 males between the ages of 18 and 24. that sample
soldier1979 [14.2K]
The 99% confidence interval for the true mean is given by:

\bar{x}\pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}

where: 

\bar{x} is the sample mean = 69.7
\sigma is the standard deviation = 2.8
z_{\alpha/2} is the test statistics = 2.58 for for 99% confidentce interval.
n is the sample size = 772.

Therefore, the 99% confidence interval is:

69.7\pm2.58\left( \frac{2.8}{\sqrt{772}} \right)=69.7\pm2.58(0.1008) \\  \\ =69.7-0.26\leq\mu\leq69.7+0.26 \\  \\ =69.44\leq\mu\leq69.96
6 0
3 years ago
Read 2 more answers
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